Question

you have a reservoir held at a constant temperature of –30°c. you add 400 j of heat to the reservoir. if you have another reservoir at 0°c, how much heat must you add to it so that both reservoirs have the same increase in entropy? (1 point)

Answer 1

$449.38 Joule$  of heat must be added up to the second reservoir to make both reservoirs have the same increase in entropy.

Entropy is the measure of systems thermal energy per unit temperature.

Mathematically,

        Entropy = $\frac{Heat}{Temperature}$

            ΔS =  $\frac{Q}{T_{Avg} }$

  For reservoir first ,

Q (heat) =  400 J

Temperature =  $-30$°  C  = $-30$° +  273 K

                        =  243K

Therefore ,

                   ΔS = $\frac{400}{243}$ J/K

For second reservoir,

Q = ?

Temperature  = 0° C + 273°

                       = 273 K

ΔS = $\frac{Q}{273}$

According to question, Entropy of both the systems are same

Therefore,

           $\frac{Q}{273}$ =  $\frac{400}{243}$ J/K

           Q =  $\frac{400*273}{243}$   J  

           Q = 449.38 J

To know more about Entropy,

brainly.com/question/1859555

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