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kompoz [17]
3 years ago
8

How to solve this equation

Mathematics
1 answer:
8_murik_8 [283]3 years ago
3 0

\bold{Hey\ there!}

  • \bold{x^2=81}
  • \bold{Take\ your\ particular\ root\ (square\ root\ preferably)}
  • \rightarrow{\bold{x=\pm\sqrt{81}}}
  • \bold{\frac{\sqrt{81}}{9}=9}
  • \boxed{\boxed{\bold{Answer:x\rightarrow9\ or\ x\rightarrow-9}}}\checkmark

\bold{Good\ luck\ on\ your\ assignment\ \& \ enjoy\ your\ day!}

~\frak{LoveYourselfFirst:)}

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f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2
iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4,\infty)

g(x)=2x^2+8x+6=2(x^2+4x+3)

g(x)=0

2(x^2+4x+3)=0

x^2+4x+3=0

x^2+3x+x+3=0

x(x+3)+1(x+3)=0

(x+1)(x+3)=0

x+1=0\implies x=-1

x+3=0\implies x=-3

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2

g(x)=2(x^2+4x)+6

g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6

g(x)=2(x+2)^2-2

By comparing with the equation of parabola

y=a(x-h)^2+k

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2,\infty)

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0
3 years ago
Traveling with the current a certain boat went 16km/h. Against the same current it only went 6km/h. Find the current and the spe
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Answer:

Step-by-step explanation:

b and c are the speeds of the boat in stool water, and current, respectively.

Going with the current, the boat travels b+c=16 km/h.

Going against the current, the boat travels b-c=6 km/h

add the equations together

b+c = 16

b-c = 6

—————

2b = 22

b = 11

c = 16-b = 5

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Ostrovityanka [42]
What is it that I am supposed to be doing?
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AURORKA [14]

Answer:

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Hope you can understand

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