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kompoz [17]
4 years ago
8

How to solve this equation

Mathematics
1 answer:
8_murik_8 [283]4 years ago
3 0

\bold{Hey\ there!}

  • \bold{x^2=81}
  • \bold{Take\ your\ particular\ root\ (square\ root\ preferably)}
  • \rightarrow{\bold{x=\pm\sqrt{81}}}
  • \bold{\frac{\sqrt{81}}{9}=9}
  • \boxed{\boxed{\bold{Answer:x\rightarrow9\ or\ x\rightarrow-9}}}\checkmark

\bold{Good\ luck\ on\ your\ assignment\ \& \ enjoy\ your\ day!}

~\frak{LoveYourselfFirst:)}

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Which expression represents the sixth term in the binomial expansion of (5y + 3)10? 10C5(5y)5(3)5 10C6(5y)4(3)6 510C5(y)5(3)5 51
DiKsa [7]

Answer:

The sixth term of the binomial expansion is;

10C5 (5y)^5 (3)^5

Step-by-step explanation:

Here, we want to select which of the options represent the 6th term of the binomial expansion;

(5y + 3)^10

We should know that while the powers of 5y will be increasing, the powers of 3 will be decreasing.

We can write the terms as follows;

10C0(5y)^10(3)^0 + 10C1(5y)^9(3)^1 + 10C2(5y)^

8(3)^2 + 10C3(5y)^7(3)^3 + 10C4(5y)^6(3)^4 + 10C5(5y)^5(3)^5 + ............

4 0
3 years ago
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BEST ANSWER WILL GET BRAINLIEST. Consider the table below. For what value of x does f(x)=-1f(x)=−1 ?
kkurt [141]

The correct answer would be 3. f(x) = -1, so you got to find the -1 in the y row of the table and just say that x =3 if y =-1.

6 0
3 years ago
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The area of a rectangular city park is 25/54 square miles. The length of the park is 5/9 mile. What is the width, in miles, of t
Natali5045456 [20]
Area of rectangle = 24/54 square miles
length(L) = 5/9 miles
width (W)= ?
area = L * W
25/54 = 5/9 * W
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5 0
3 years ago
Can somebody help me make the 2 equations for each problem. I'm confuzzled
NikAS [45]
We can't see #2 so therefore we can not answer it
8 0
3 years ago
Help me pls pls pls​
valina [46]

Answer:

Since the input values are -7/2 and 2. So the answer is C.

Step-by-step explanation:

Given that when x-value is substituted into the function, you get 19. So in order to find the input value (x), you have to make the function equals 19 :

f(x) = 2 {x}^{2}  + 3x + 5

let \: f(x) = 19

2 {x}^{2}  + 3x + 5 = 19

Next, you have to factorize it :

2 {x}^{2}  + 3x + 5 - 19 = 0

2 {x}^{2}  + 3x - 14 = 0

2 {x}^{2}  + 7x - 4x - 14 = 0

x(2x + 7) - 2(2x + 7) = 0

(x - 2)(2x + 7) = 0

Lastly, solve it :

x - 2 = 0

x = 2

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