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3 years ago

Includes both the speed of an object and the direction if it moving

Physics

1 answer:

frez [133]3 years ago

5 0

That is called velocity. Which is acceleration in a direction.

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Based on the images seen here, identify which phase of matter would transmit light waves the fastest, and why?

Mila [183]

Answer: the 3rd one

Explanation:

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3 years ago

Read 2 more answers

Physical science

attashe74 [19]

Answer:

0.56 km/s

Explanation:

We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.

$560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s]$

Therefore the speed of 0.56 [km/s] is the greatest of all

3 0

4 years ago

Which part of a circuit can be turn on and off to make an electromagnet work or stop

Charra [1.4K]

Answer:The electric current

Explanation:

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3 years ago

A charge q = 3 × 10-6 C of mass m = 2 × 10-6 kg, and speed v = 5 × 106 m/s enters a uniform magnetic field. The mass experiences

NeX [460]

Answer:

Magnetic field, B = 0.004 mT

Explanation:

It is given that,

Charge, $q=3\times 10^{-6}\ C$

Mass of charge particle, $m=2\times 10^{-6}\ C$

Speed, $v=5\times 10^{6}\ m/s$

Acceleration, $a=3\times 10^{4}\ m/s^2$

We need to find the minimum magnetic field that would produce such an acceleration. So,

$ma=qvB\ sin\theta$

For minimum magnetic field,

$ma=qvB$

$B=\dfrac{ma}{qv}$

$B=\dfrac{2\times 10^{-6}\ C\times 3\times 10^{4}\ m/s^2}{3\times 10^{-6}\ C\times 5\times 10^{6}\ m/s}$

B = 0.004 T

B = 4 mT

So, the magnetic field produce such an acceleration at 4 mT. Hence, this is the required solution.

4 0

3 years ago

A ray of light traveling in air is incident on the flat surface of a piece of glass at an angle of 65.9° with respect to the nor

stich3 [128]

Answer:

$n_{glass}$ = 1.6

Explanation:

$\theta _{i}$ = Angle of incidence = 65.9°

$\theta _{r}$ = Angle of refraction = 34.8°

$n_{air}$ = Index of refraction of air = 1

$n_{glass}$ = Index of refraction of glass = ?

Using Snell's law

$n_{air}$ Sin $\theta _{i}$ = $n_{glass}$ $\theta _{r}$

(1) Sin65.9 = $n_{glass}$ Sin34.8

$n_{glass}$ = 1.6

6 0

4 years ago