The approximate acceleration of the car would be <span>3.00
</span>How? We have to use the formula to find the velocity.
v = d/t = 120/6.32
v = 19
Then plug the factor into the acceleration formula to find the acceleration:
a = v/t = 19/6.32
a = 3.00
So, the approximate acceleration of the car would be 3.00
Answer:
9.26 km/h
Explanation:
Applying,
V' = D'/t'............... Equation 1
Where V' = Average speed, D' = Total distance, t' = total time.
Given: D' = 5 km
But,
v = d/t............ Equation 2
Where v = speed , d = distance, t = time
t = d/v............ Equation 3
Given: d = 4.5 km, v = 9 km/h, and d = 0.5 km, v = 12.5 km/h
Therefore,
t₁ = 4.5/9 = 0.5 hours
t₂ = 0.5/12.5
t₂ = 0.04 hours
Therefore,
V' = 5/(0.5+0.04)
V' = 5/0.54
V' = 9.26 km/h
Answer:
intinal speed should be 10
Explanation:
v = v0 + at
30 = v0 +10.2
then v0= 10
Answer:
They are too busy doing their own work
