Answer:
20.7N
Explanation:
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Answer:
B.electromagnetic spectrum
Explanation:
Electromagnetic spectrum is used to describe all of the wavelengths of light waves.Generally wavelength of the wave is denoted by λ.
Wavelength is the distance between two consecutive crest .Wavelength of the red color is minimum and wavelength of the violet color is maximum in the light spectrum.
So the answer is B.
Electromagnetic spectrum
Answer:
The gravitational acceleration is same for all objects.
a = b = c = d
Explanation:
Acceleration due to gravity or gravitational acceleration is the force exerted by Earth on unit mass of an object.
Acceleration due to gravity doesn't depend on the height of the object when the height is object is near to the surface of the Earth. Only when the height is comparable to the radius of the Earth, the value of gravitational acceleration changes.
But for the objects here, the gravitational acceleration is independent of the mass or height of the objects and has a constant value of 9.8 m/s².
Therefore, the gravitational acceleration of all the objects is same.
If 'a', 'b', 'c', and 'd' represent gravitational accelerations of objects 'a', 'b', 'c', and 'd' respectively, then a = b = c = d.
Answer:
16.32 °C
Explanation:
We are given;
Mass of aluminum bowl; m_b = 0.25 kg
Mass of soup; m_s = 0.8 kg
Thus, formula to find the amount of heat energy for a temperature change of 27.6°C to 0°C is;
Q = (m_b•c_b•Δt) + (m_s•c_s•Δt)
Where;
c_b = 0.215 kcal/(kg•°C)
c_s = 1 kcal/(kg•°C)
ΔT = 27.6 - 0 = 27.6°C
Thus;
Q = (0.25 × 0.215 × 27.6) + (0.8 × 1 × 27.6)
Q = 23.5635 Kcal
Now, the energy that exits to be used to freeze the soup is;
Q' = 424 kJ - Q
Let's convert 424 KJ to Kcal
424 KJ = 424/4.184 Kcal = 101.3384 Kcal
Thus;
Q' = 101.3384 - 23.5635
Q' = 77.7749 Kcal
Amount of heat that's removed is given by;
Q_f = Q' - mL
Where;
m = m_s = 0.8 kg
L = 79.8 kcal/kg
Thus;
Q_f = 77.7749 - (0.8 × 79.8)
Q_f = 13.9349 Kcal
Then final temperature will be;
T_f = Q_f/((m_b•c_b) + (m_s•c_s))
T_f = 13.9349/((0.25 × 0.215) + (0.8 × 1))
T_f = 16.32 °C
