In a class 30 of students, 13 have a cat and 7 have a dog. There are 4 students who
1 answer:
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Volume of pyramid:
A - base area
H - height
First count volume of one pyramid:
![V=\dfrac{1}{3} \cdot 3 \cdot 4=4 [\hbox{inch}^3]](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B1%7D%7B3%7D%20%5Ccdot%203%20%5Ccdot%204%3D4%20%5B%5Chbox%7Binch%7D%5E3%5D)
So by using 576 inch^3 you can make 576 : 4 = 144 pyramids
A - base area
H - height
First count volume of one pyramid:
So by using 576 inch^3 you can make 576 : 4 = 144 pyramids
Answer:
Step-by-step explanation:
a) The probability that the hand contains exactly one ace
No of ways of selecting one ace and four non ace would be
=
i.e. α=778320
b) the probability that the hand is a flush
No of ways of getting a flush is either all 5 hearts or clubs of spades or dice
=
ie. β=5148
c) the probability that the hand is a straight flush
In each of the suit to get a straight flush we must have either A,2,3,4,5 or 2,3,4,5,6, or .... or 9,10, J, q, K
So total no of ways =
γ=46332