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mamaluj [8]
3 years ago
11

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Divide the following polynomial and then place the answer in the proper location on the grid.

8y 7 ÷ 4y 5
Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

2y^2. 8/4 = 2 and y^7/y^5 is y^2 i don't know if this is what you completely asked for but here is the answer

Step-by-step explanation:

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Graph the line with slope -8 and y-intercept 9.
salantis [7]

Answer:

the coordinates will be (0,9) (-8,0) and the equation will be y=(9/8x)+9

Step-by-step explanation:

Im not 100% sure but if im right please mark me as brainliest

8 0
3 years ago
if you put $1650 into a saving account with a simple interest rate of 2.3%, how much interest would you accrue after 7 years
Ber [7]
You would recieve $37.95 a year then multiply that by 7 years to get $265.65
6 0
3 years ago
Can someone please help me with this question thank you
netineya [11]

Answer:

The answers are C,F

Step-by-step explanation:

Those are the coordinates where the lines intercept the x-axis.

3 0
3 years ago
10 feet wide by 30 feet long by 1/3 foot deep.what is the volume?
Ket [755]
----------------------------------------------
Formula
----------------------------------------------
Volume = Length x Width x Height

----------------------------------------------
Apply Formula
----------------------------------------------
Volume = 10 x 30 x 1/3 = 100 ft³

----------------------------------------------
Answer: 100 ft³
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4 0
2 years ago
Read 2 more answers
If G(x) = 3x + 1, then G -1(1) is<br> 4<br> 1/3<br> 0
Eduardwww [97]

Answer:

0


Step-by-step explanation:

g(x) = 3x + 1 \\\ y = 3x + 1


Changing x to y and y to x:


x = 3y + 1 \\\ 3y = x - 1 \\\ y = \frac{x - 1}{3} \\\ g^{-1}(x) = \frac{x - 1}{3} \\\ g^{- 1} (1) = \frac{1 - 1}{3} \\\ g^{- 1} (1) = 0


I hope I helped you.

4 0
2 years ago
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