Your answer is the first option -4<x<_4
Remember
ou can do anything to an equaiotn as long as you do it to both sides
try to isolate variable and get 1 of it
-6+5b=6b-7
subtract 5b from both sides
-6=b-7
add 7
1=b
Answer:
Step-by-step explanation:
Given that,
μ = 25.1
σ = 0.26
a) since standard deviation is ideal measure of dispersion , a combination of control chart for mean x and standard deviation known as

Chart is more appropriate than
and R - chart for controlling process average and variability
so we use
charts
b)
n = 11
we have use 2 σ confidence
so, control unit for
chart are
upper control limit = 
lower control limit = 
control limit = μ
μ = 25.1
upper control limit =

lower control limit =

Upper control limit and lower control limit are in between the specification limits , that is in between 24.9 and 25.6
so, process is in control
c) if we use 3 sigma limit with n = 11
then
upper control limit = 

lower control limit = 

control limit is 25.1
Then, process is in control since upper control limit and lower control limit lies between specification limit
So, process is in control
If you would like to know what is the product of (6 * x^3 + 3 * x) * (x^2 + 4), you can calculate this using the following steps:
(6 * x^3 + 3 * x) * (x^2 + 4) = 6 * x^3 * x^2 + 6 * 4 * x^3 + 3 * x * x^2 + 3 * 4 * x = 6 * x^5 + 24 * x^3 + 3 * x^3 + 12 * x = 6 * x^5 + 27 * x^3 + 12 * x
The correct result would be 6 * x^5 + 27 * x^3 + 12 * x.