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ira [324]
3 years ago
7

In the gaseous state, chlorine exists as a diatomic molecule Cl2 (Molar mass = 70.9 g/mol). Calculate the number of moles of chl

orine present in 140 g of chlorine gas. Express the quantity in moles to three significant figures.
Chemistry
1 answer:
kap26 [50]3 years ago
8 0

Cl is stable as a diatomic molecule where the 2 Cl atoms are held together by a covalent bond

molar mass of the diatomic molecule is 70.9 g/mol

therefore 70.9 g of Cl₂ is - 1 mol

then 140 g of Cl₂ is - 1/70.9 x 140 = 1.97 mol

there are 1.97 mol of Cl₂ present

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<h2>Part 1: Naming compound formulas given the names</h2>

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<u>Step 2:</u> Oxygen is a diatomic molecule (it exists bonded to itself for stability purposes), so by itself in chemical equations, it is written as O_2.

<u>Step 3:</u> Carbon dioxide is the molecular compound of one atom of carbon and two atoms of oxygen → CO_2.

<u>Step 4:</u> Water is the common name of the compound of two hydrogen atoms and one oxygen atom → H_2O.

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<u>Step 1:</u><em> </em>Use the determined formulas for the reactants and plug them into the equation. We are told that methane burns in oxygen -- hinting at a combustion reaction. Therefore, we may infer that these are the reactants that yield the products.

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Because the problem asks for the unbalanced equation, we do not need to take any further steps of balancing the equation.

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