<span>(a) what is the average volume (in cubic meters) required for each iron atom
For this case, the density of Iron would be </span>7.87g/cm³
<span>
V = 9.27 x 10^-26 kg / </span>7.87g/cm<span>³ ( 1 kg / 1000 g)
</span>V = 1.18 x 10-23 cm³<span>
(b) what is the distance (in meters) between the centers of adjacent atoms?
We assume the atoms as cube, so we use the volume of the cube to calculate the distance of the atoms.
V = </span>1.18 x 10-23 cm<span>³ = s</span>³
s = 2.28 x 10^-8 cm
Answer: Chyme
Explain: Chyme passes from the stomach to the small intestine. Further protein digestion takes place in the small intestine.
Moles of potassium permanganate = 0.0008
<h3>Further explanation </h3>
Titration is a procedure for determining the concentration of a solution by reacting with another solution which is known to be concentrated (usually a standard solution). Determination of the endpoint/equivalence point of the reaction can use indicators according to the appropriate pH range
Reaction
5Na2C2O4(aq) + 2KMnO4(aq) + 8H2SO4(aq) ---> 2MnSO4(aq) + K2SO4(aq) + 5Na2SO4(aq) + 10CO2(g) + 8H2O(1)
The end point ⇒titrant and analyte moles equal
titrant : potassium permanganate-KMnO4
analyte : sodium oxalate - Na2C2O4
so moles of KMnO4 = moles of Na2C2O4
moles of Na2C2O4(mass = 0.2640 g, MW=134 g/mol) :

From equation, mol ratio Na2C2O4 : KMnO4 = 5 : 2, so mol KMnO4 :

Your answer is B. It gets energy from the Sun.
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Answer:
FALSE
Explanation:
Assuming that the gas is ideal
Therefore the gas obeys the ideal gas equation
<h3>Ideal gas equation is </h3><h3>P × V = n × R × T</h3>
where
P is the pressure exerted by the gas
V is the volume occupied by the gas
n is the number of moles of the gas
R is the ideal gas constant
T is the temperature of the gas
Here volume of the gas will be the volume of the container
Given the volume of the container and number of moles of the gas are constant
As R will also be constant, the pressure of the gas will be directly proportional to the temperature of the gas
P ∝ T
∴ Pressure will be directly proportional to the temperature