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son4ous [18]
2 years ago
5

How many oxygen (O) atoms are in a molecule of C3H403? O A. 1 O B. 10 O c. 4 O D. 3

Chemistry
2 answers:
sleet_krkn [62]2 years ago
6 0

Answer:

your answer is 3

Explanation:

Natali5045456 [20]2 years ago
3 0

Answer:

D

Explanation:

"O3" means there are three atoms of that particle element in the substance.

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Selected properties of antimony (Sb) and iodine (I) are listed in the table below. Element Atomic radius (pm) First ionization e
Effectus [21]

Let us check each statement one by one

a) Sb has a lower ionization energy but a higher electronegativity than I. : As per values given : Definitely Sb has lower ionization energy however the electronegativity of Sb is lower than that of iodine

b) Sb has a higher ionization energy but a lower electronegativity than I. FAlse:

Sb has lower ionization energy than I

c) Sb has a lower ionization energy and a lower electronegativity than I. True

d) Sb has a higher ionization energy and a higher electronegativity than I. False


4 0
3 years ago
Read 2 more answers
The basic building blocks of a protein are
snow_lady [41]


The building  blocks of protein are amino acids.

Amino acids are a class of organic compounds that contain at least one amino group, -NH2, and carboxyl group, -COOH.

Alpha amino acids , RCH(NH2)COOH, are the building blocks  from which proteins are constructed.

The NH group of one amino acid and the COOH  group of the other amino acid are joined together and a peptide bond -CONH-  is formed between the two amino acids and the product is called a dipeptide.





5 0
2 years ago
An electron in the hydrogen atom makes a transition from an energy state of principal quantum number ni to the n = 2 state. If t
topjm [15]

Answer:

\boxed{3}

Explanation:

The Rydberg equation gives the wavelength λ for the transitions:

\dfrac{1}{\lambda} = R \left ( \dfrac{1}{n_{i}^{2}} - \dfrac{1}{n_{f}^{2}} \right )

where

R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and

\text{$n_{i}$ and $n_{f}$ are the numbers of the energy levels}

Data:

n_{f} = 2

λ = 657 nm

Calculation:  

\begin{array}{rcl}\dfrac{1}{657 \times 10^{-9}} & = & 1.0974 \times 10^{7}\left ( \dfrac{1}{2^{2}} - \dfrac{1}{n_{f}^{2}} \right )\\\\1.522 \times 10^{6} &= &1.0974\times10^{7}\left(\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \right )\\\\0.1387 & = &\dfrac{1}{4} - \dfrac{1}{n_{f}^{2}} \\\\-0.1113 & = & -\dfrac{1}{n_{f}^{2}} \\\\n_{f}^{2} & = & \dfrac{1}{0.1113}\\\\n_{f}^{2} & = & 8.98\\n_{f} & = & 2.997 \approx \mathbf{3}\\\end{array}\\\text{The value of $n_{i}$ is }\boxed{\mathbf{3}}

7 0
2 years ago
Which subatomic particles affect the mass of an atom
klasskru [66]

Answer:

protons and neutrons

Explanation:

those particles account for 99.99% of mass

6 0
2 years ago
3. When two atoms of 2H (deuterium) are fused to form one atom of 4He (helium), the total energy evolved is 3.83 × 10-12 joules.
balandron [24]
3.
∆E = ∆m x c ² ∆m = E / c ² ∆m = 3,83•10^-12 / 3•10^8 ² ∆m = 4,256•10^-29 kg

Taking this class as well 
6 0
3 years ago
Read 2 more answers
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