We will use the expression for freezing point depression ∆Tf
∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is
∆Tf = 0C - (-3°C) = 3°C
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and one Cl- ion:
KCl → K+ + Cl-
Therefore, the molality m of the solution can be calculated as
3 = 2 * 1.86 * m
m = 3 / (2 * 1.86)
m = 0.80 molal
<span> If you want to lift something that weighs
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1000N (newtons). I hope this helps, please mark brainiest if it does. I will attach a picture I found off the internet to further help you :)
(There are like 1,000,000,000,000,000,000,000 other ways I could have put that, to make it sound less creepy, I could just edit it now instead of writing this huge thing... oh well lol)
</span>
Answer:
A chemical change is a change in the chemical makeup of a substance and results in a new substance. Ice and water both have the same chemical makeup - ice is just a different state and has the same atoms but in an expanded form.
Explanation:
Answer:
4244.48 g to the nearest hundredth.
Explanation:
The molar mass of Glucose = 6*12.011 + 12*1.008+ 6*15.999
= 180.156.
So 23.56 moles = 180.156 * 23.56 = 4244.48 g