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ivanzaharov [21]
4 years ago
7

A convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -2.2 m . an object is 4.4 m from the mi

rror.
Physics
1 answer:
Maksim231197 [3]4 years ago
4 0
The question is missing, but I guess the problem is asking for the location of the image.

We can solve the problem by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i}
where
f is the focal length of the mirror
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

For a convex mirror, the focal length is taken as negative, so in our problem 
f=-2.2 m
The distance the object is
d_o=4.4 m

And if we use the previous equation, we can find the distance of the image from the mirror:
\frac{1}{d_i}= \frac{1}{f}- \frac{1}{d_o}= -\frac{1}{2.2 m} - \frac{1}{4.4 m}    =- \frac{3}{4.4 m}
from which we find
d_i =  -\frac{4.4 m}{3}=-1,47 m
where the negative sign means the image is virtual (located behind the mirror)
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Given parameters:

Mass of object = 6.7kg

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Unknown parameter:

Kinetic energy  = ?

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Kinetic energy is the energy due to the motion of a body. Whereas, potential energy is the energy due to the position of a body usually at rest.

Kinetic energy is mathematically expressed as;

             Kinetic energy  = \frac{1}{2} m v^{2}

where m is the mass of the body

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Since we have been given both mass and velocity, input the parameter to solve for the unknown;

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3 years ago
A property unique to a conducting substance that determines its resistance is called:
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Answer:

B. Resistivity

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A proton moving at 3.0 × 10^4 m/s is projected at an angle of 30° above a horizontal plane. If an electric field of 400 N/C is a
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Answer:

The time it takes the proton to return to the horizontal plane is 7.83 X10⁻⁷ s

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Dividing both equations by mass;

F/m = Eq/m = mg/m, then

g = Eq/m --------equation 1

Again, in a projectile motion, the time of flight (T) is given as

T = (2usinθ/g) ---------equation 2

Substitute in the value of g into equation 2

T = \frac{2usin \theta}{\frac{Eq}{m}} =\frac{m* 2usin \theta}{Eq}

Charge of proton = 1.6 X 10⁻¹⁹ C

Mass of proton = 1.67 X 10⁻²⁷ kg

E is given as 400 N/C, u = 3.0 × 10⁴ m/s and θ = 30°

Solving for T;

T = \frac{(1.67X10^{-27}* 2*3X10^4sin 30}{400*1.6X10^{-19}}

T = 7.83 X10⁻⁷ s

6 0
3 years ago
Suppose for your cookout you need to make 100 hamburgers. You know that 2.00 pounds will make 9 hamburgers. How many pounds will
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1. The distance between a trough and a crest on a transverse wave is 12.0cm. If cycles of the wave pass a fixed point in one sec
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Answer:

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2 years ago
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