1. The distance between a trough and a crest on a transverse wave is 12.0cm. If cycles of the wave pass a fixed point in one sec
1 answer:
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Five
The diagram that represents rays from the sun is given below.
The answer from the diagram is parallel lines.
Six
The formula for this is n_i * Sin(i) = n_r * sin(r)
n1 = 1.333 water
n2 = 1.309 ice
i (angle) = 40o
r (angle) = ?
Solution
1.333 * sin(40) = 1.309*sin(r)
1.333 * sin(40)/1.309 = sin(r)
0.6546 = sin(r)
sin-1(0.6546) = 40.88 degrees.
I guess my closest answer would be A. I'm not rounding at all and that's the answer I get.
