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OverLord2011 [107]
3 years ago
10

You need to order at least 10 soccer balls for your little brother’s team. Practice soccer balls cost $6 and game soccer balls c

ost $8. The coach gave you $96 to spend.
Mathematics
1 answer:
Triss [41]3 years ago
8 0
What r u trying to figure out
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Order the numbers in each list from least to greatest. 0, |-14|, 13 , -12, |-16|, 17
jeka57 [31]

Here is your answer:

In order to find the answer you must first find the absolute value of each number, then order them from least to greatest.

  • 0 = 0
  • I-14I = 14
  • 13 = 13
  • -12 = 12
  • I-16I=16
  • 17 = 17
  • Now least to greatest:
  • -12,0,13,14,16,17

Therefore the answer is "-12,0,13,14,16,17."

Hope this helps!

4 0
3 years ago
Read 2 more answers
4. Suppose Tyler sprayed around the house for ants. Which formula would be used to find the number of ants still alive after a c
babunello [35]

Answer:

I think that the answer is A.

Step-by-step explanation:

6 0
3 years ago
What is the answer pls hurry!!
Mkey [24]

Answer:

the answer is 16.3452

Step-by-step explanation:

I hope it was helpful

5 0
3 years ago
How to find left and right inverse of a 3x2 matrix.
Mnenie [13.5K]

Let A be a 3×2 matrix, L its left inverse, and R its right inverse. L and R are then matrices such that LA = I₂ (the 2×2 identity matrix) and AR = I₃ (the 3×3 identity matrix). Clearly L must be 2×3 and R must be 3×2 in order for the matrix products to be defined.

To find L and R, we start by introducing a square matrix on the the left sides of either equation above. In particular, we uniformly multiply both sides by the transpose of A, then solve for the inverse.

For the left inverse, we have

LA=I

(LA)A^\top = IA^\top

L\left(AA^\top\right) = A^\top

\left(L\left(AA^\top\right)\right)\left(AA^\top\right)^{-1} = A^\top \left(AA^\top\right)^{-1}

L\left(\left(AA^\top\right)\left(AA^\top\right)^{-1}\right) = A^\top \left(AA^\top\right)^{-1}

LI = A^\top \left(AA^\top\right)^{-1}

L = A^\top \left(AA^\top\right)^{-1}

We do the same thing for the right inverse, but take care with how we multiply both sides of AR = I₃.

AR=I

A^\top(AR)=A^\top I

\left(A^\top A\right)R = A^\top

\left(A^\top A\right)^{-1} \left(\left(A^\top A\right)R\right) = \left(A^\top A\right)^{-1} A^\top

\left(\left(A^\top A\right)^{-1} \left(A^\top A\right)\right) R = \left(A^\top A\right)^{-1} A^\top

IR = \left(A^\top A\right)^{-1} A^\top

R = \left(A^\top A\right)^{-1} A^\top

4 0
3 years ago
What is the solution to the inequality? 4x−5>19−8x
Nostrana [21]

Answer:

x>1.16

Step-by-step explanation:

Subtract 5 from each side to get 4x>14-8x

change the symbol from +8 to -8

4x> 14+ (-8x)

than add 8x to both sides

12x > 14

which would mean that x has to be greater than 1.16

x>1.16

7 0
3 years ago
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