Heat
gained in a system can be calculated by multiplying the given mass to the
specific heat capacity of the substance and the temperature difference. It is
expressed as follows:<span>
Heat = mC(T2-T1)
When two objects are in contact,
it should be that the heat lost is equal to what is gained by the other. From
this, we can calculate things. We do as follows:
<span>Heat gained =
Heat lost</span>
mC(T2-T1) = - mC(T2-T1)
C(liquid water) = 4.18 J/gC
C(ice) = 2.11 J/gC
</span><span>(354 mL)(1.0 g/mL)(4.18 J/gC)(26 C - 6 C) = m(2.11 J/gC)(6 - 0C) </span><span>
m = 2337.63 g of ice
</span>
The answer is b because if you’re fan is blowing and you spend it the opposite way, the air will be cooler
Explanation:
Carbon monoxide and hydrogen gas reacts together to form methanol:
CO + 2H2 => CH3OH
Since 0.266mol * 2 = 0.532mol > 0.524mol, the limiting reactant here is hydrogen and therefore there will be 0.524mol / 2 = 0.262mol of methanol.
Answer:
ΔG = -6.5kJ/mol at 500K
Explanation:
We can find ΔG of a reaction using ΔH, ΔS and absolute temperature with the equation:
ΔG = ΔH - TΔS
Computing the values in the problem:
ΔG = ?
ΔH = 2kJ/mol
T = 500K
And ΔS = 0.017kJ/(K•mol)
Replacing:
ΔG = 2kJ/mol - 500K*0.017kJ/(K•mol)
ΔG = 2kJ/mol - 8.5kJ/mol
<h3>ΔG = -6.5kJ/mol at 500K</h3>
