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yanalaym [24]
3 years ago
15

The drug molecules bind the protein in a 1:1 ratio to form a drug-protein complex. The protein concentration in aqueous solution

at 25 ∘C is 1.60×10−6 M . Drug A is introduced into the protein solution at an initial concentration of 2.00×10−6M. Drug B is introduced into a separate, identical protein solution at an initial concentration of 2.00×10−6M. At equilibrium, the drug A-protein solution has an A-protein complex concentration of 1.00×10−6M, and the drug B solution has a B-protein complex concentration of 1.40×10−6M.a. Calculate the Kc value for the A-protein binding reaction.b. Calculate the Kc value for the B-protein binding reaction.c. Assuming that the drug that binds more strongly will be more effective, which drug is the better choice for further research?
Chemistry
1 answer:
Sati [7]3 years ago
5 0

Answer:

a. kc = 1,67x10⁶

b. kc = 1,17x10⁷

c. Drug B is the better choice.

Explanation:

The bind of drug-protein is described as:

Protein + Drug ⇄ Drug-protein

Where kc is:

kc = [Drug-protein] / [Protein] [Drug] <em>(1)</em>

a. For A, the equilibrium concentration of each specie is:

[Protein]: 1,60x10⁻⁶M - x

[Drug]: 2,00x10⁻⁶M - x

[Drug-protein]: x = <em>1,00x10⁻⁶M </em>

<em>-Where x is reaction coordinate-</em>

Thus:

[Protein]: 1,60x10⁻⁶M - 1,00x10⁻⁶M = <em>0,60x10⁻⁶M</em>

[Drug]: 2,00x10⁻⁶M - 1,00x10⁻⁶M = <em>1,00x10⁻⁶M</em>

Replacing in (1):

kc = [1,00x10⁻⁶] / [1,00x10⁻⁶] [0,60x10⁻⁶]

<em>kc = 1,67x10⁶</em>

<em />

b. For B:

[Protein]: 1,60x10⁻⁶M - x

[Drug]: 2,00x10⁻⁶M - x

[Drug-protein]: x = <em>1,40x10⁻⁶M </em>

<em>-Where x is reaction coordinate-</em>

Thus:

[Protein]: 1,60x10⁻⁶M - 1,40x10⁻⁶M = <em>0,20x10⁻⁶M</em>

[Drug]: 2,00x10⁻⁶M - 1,40x10⁻⁶M = <em>0,60x10⁻⁶M</em>

Replacing in (1):

kc = [1,40x10⁻⁶] / [0,20x10⁻⁶] [0,60x10⁻⁶]

<em>kc = 1,17x10⁷</em>

<em />

c. The drug with the bigger kc will be the more effective because will be the drug that binds more strongly with the protein. Thus, <em>drug B is the better choice.</em>

I hope it helps!

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