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trasher [3.6K]
2 years ago
9

What is the volume, in liters, of 13.5 moles of a gas at STP? (STP = 273.15K, 1 atmosphere)

Chemistry
1 answer:
RideAnS [48]2 years ago
4 0

Answer:

302.75 Liters

Explanation:

Given:

P = 1 atm

V = ?

n = 13.5 moles

R = 0.0821 atm x L / mole x K

T = 273.15 K

PV = nRT

(1) (V) = (13.5) (0.0821) (273.15)

V = 302.75 Liters

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How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)
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You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

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After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200.  * 1 = 200

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Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

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Ka (mol/L ) = <span>0.00002340</span>

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