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ruslelena [56]
3 years ago
13

What sound frequency would a human ear not be able to detect?

Chemistry
1 answer:
koban [17]3 years ago
6 0

Answer: A: 10

Explanation:

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Convert 23.92inHg to Pa.
andriy [413]

Answer:

3189.07Pa

Explanation:

The conversion of 23.92mmH to Pa can be achieved in the following way:

760mmHg = 101325Pa

23.92mmHg = (23.92x101325)/760 = 3189.07Pa

5 0
3 years ago
Read 2 more answers
What volume (in L) of carbon dioxide will be produced from the reaction of 37.4 L of oxygen?
Anna [14]

Answer:

21.4 L

Explanation:

Given data:

Volume of carbon dioxide produced = ?

Volume of oxygen  = 37.4 L

Solution:

Chemical equation:

2C₂H₆ + 7O₂  →  4CO₂ + 6H₂O

It is known that,

1 mole = 22.414 L

There are 7 moles of oxygen = 7×22.414 = 156.9 L

There are 4 moles of carbon dioxide = 4×22.414 = 89.66 L

Now we will compare:

                              O₂             :              CO₂    

                              156.9         :              89.66

                                37.4         :             89.66/156.9×37.4 = 21.4 L

So from 37.4 L of oxygen 21.4 L of carbon dioxide is produced.

3 0
3 years ago
Why do atoms form bonds
dimaraw [331]
Atoms tend to form bonds because one atom may have more attraction to electrons than the other<span />
5 0
4 years ago
Read 2 more answers
8g of aqueous Sodium Hydroxide reacts with 4g of aqueous Aluminum Chloride to produce aqueous Sodium Chloride and solid Aluminum
slava [35]

Answer:

The limiting reactant is AlCl₃ and the excess reactant is NaOH.

Explanation:

  • The balanced equation for the mentioned reaction is:

<em>3NaOH(aq) + AlCl₃(aq) → 3NaCl(aq) + Al(OH)₃(s)↓,</em>

It is clear that 3.0 moles of NaOH(aq) react with 1.0 mole of AlCl₃(aq) to produce 3.0 moles of NaCl(aq) and 1.0 mole of Al(OH)₃(s).

  • Firstly, we need to calculate the no. of moles of (8.0 g) of NaOH and (4.0 g) of AlCl₃:

no. of moles of NaOH = mass/molar mass = (8.0 g)/(40.0 g/mol) = 0.2 mol.

no. of moles of AlCl₃ = mass/molar mass = (4.0 g)/(133.34 g/mol) = 0.03 mol.

  • From stichiometry; NaOH reacts with AlCl₃ with (3: 1) molar ratio.

∴ 0.09 mol of NaOH (the remaining 1.1 mol is in excess) reacts completely with 0.03 mol of AlCl₃.

  • So,

<em>the limiting reactant is AlCl₃ and the excess reactant is NaOH.</em>

<em></em>

6 0
3 years ago
How much heat is required to vaporize 166g of water at it's boiling point, if water's heat of vaporization is equal to 40.7kJ/mo
Anvisha [2.4K]

Answer:

375.3KJ

Explanation:

The following data were obtained from the question:

Mass of water = 166g

Heat of Vaporisation (ΔHv) = 40.7kJ/mol

Heat (Q) =..?

Next, we shall determine the number of mole in 166g of water. This is illustrated below:

Mass of H2O = 166g

Molar mass of H2O = (2x1) + 16 = 18g/mol

Number of mole = Mass/Molar Mass

Number of mole of H2O = 166/18

Number of mole of H2O = 9.22 moles.

Now, we can obtain the heat required to vaporise the water as shown below:

Q = n·ΔHv

Q = 9.22 mol x 40.7kJ/mol

Q = 375.3KJ

Therefore, the heat required to vaporise the water is 375.3KJ.

4 0
3 years ago
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