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atroni [7]
3 years ago
9

Need answer today!!!

Chemistry
1 answer:
scoray [572]3 years ago
5 0

Answer:

Calcium for 2+ charge and Fluorine forms 1- charge

Explanation:

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Which of the following reactions would result in decreased entropy? (multiple choice)
jasenka [17]

Answer:

D

Explanation:

Since the state of matter is going from a gas to a solid, it would be going from a state of high entropy (greater disorder) to a state of lower entropy (less disorder).

8 0
3 years ago
A vessel of volume 22.4 dm3 contains 20 mol h2 and 1 mol n2 ad 273.15 k initially. All of the nitrogen reacted with sufficient h
NikAS [45]

Nitrogen combine with hydrogen to produce ammonia \text{NH}_3 at a 1:3:2 ratio:

\text{N}_2 \; (g) + 3 \;  \text{H}_2 \; (g) \leftrightharpoons 2\; \text{NH}_3 \; (g)

Assuming that the reaction has indeed proceeded to completion- with all nitrogen used up as the question has indicated. 3 \; \text{mol} of hydrogen gas would have been consumed while 2 \; \text{mol} of ammonia would have been produced. The final mixture would therefore contain

  • 17 \; \text{mol} of \text{H}_2 \; (g) and
  • 2 \; \text{mol} of \text{NH}_3 \; (g)

Apply the ideal gas law to find the total pressure inside the container and the respective partial pressure of hydrogen and ammonia:

  • \begin{array}{lll} P(\text{container}) &= & n \cdot R \cdot T / V \\ & = & (17 + 2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.926 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{H}_2) &= & n \cdot R \cdot T / V \\ & = & (17) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  1.723 \times 10^{3} \; \text{kPa} \end{array}
  • \begin{array}{lll} P(\text{NH}_3) &= & n \cdot R \cdot T / V \\ & = & (2) \; \text{mol} \times 8.314 \; \text{L} \cdot \text{kPa} \cdot \text{mol}^{-1} \cdot \text{K}^{-1} \\ & &\times 273.15 \; \text{K} / (22.4 \; \text{L}) \\ &=&  2.037 \times 10^{2} \; \text{kPa} \end{array}
6 0
3 years ago
A 2-kg box is pushed from rest to a speed of 29.7 m/s in 21 seconds. What is the power require to accelerate the box.
Alona [7]

Answer:

P = 83.16 Watt

Explanation:

Given data:

Mass of box = 2 Kg

velocity of box = 29.7 m/s

Time = 21 sec

Power = ?

Solution:

Formula:

Power = work done/time

Now we will calculate the work done.

W = force × distance ...... (1)

d = speed /time

d = 29.7 m/s× 21 s

d = 623.7 m

Force:

acceleration = 29.7 m/s / 21 s

a = 1.4 m/s²

Force = m×a

Force = 2 kg×1.4 m/s²

Force = 2.8 N

Now we will put the values in equation 1.

W = F × d

W = 2.8 N ×623.7 m

W = 1746.36 Nm

Now for power:

P = W / time

P = 1746 Nm / 21 s

P = 83.16 Watt

5 0
3 years ago
Read 2 more answers
A guy swam a 50 meter freestyle in 21.93 seconds. How fast is this in miles per hour?
lara [203]

Answer:

<h2>Speed = 5.107 mile/hr</h2>

Explanation:

<h3>Given:</h3>

<u>distance</u> =50m = 0.0311 mile

<u>Time</u>= 21.93 seconds/3600 =0.00609 hour

<u>Speed</u><u>=</u>?

<h3>Speed= Distance / Time </h3><h3> = 0.0311 / 0.00609</h3><h3> = 5.107 mile/hr</h3>

5 0
3 years ago
An copper mass is heated and placed in a foam cup calorimeter containing 45.0 mL of water at 24.0 degrees celcius. The water rea
Alenkinab [10]

Answer:

= 9,593.1 Joules

Explanation:

Heat absorbed by water is equivalent to heat released by copper.

Heat absorbed is given by;

Q = mcΔT

where m is the mass, c is the specific capacity and ΔT is the change in temperature.

Therefore;

Since dnsity of water is 1 g/mL, and specific heat capacity is 4.18 J/g°C while the change in temperature is (75-24) = 51°C.

Heat absorbed by water = 45 g × 4.18 J/g°C × 51

                                         = 9,593.1 Joules

Therefore, the heat released by copper is 9,593.1 Joules

7 0
4 years ago
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