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Mnenie [13.5K]
3 years ago
14

When a piece of metal is irradiated with UV radiation (λ = 162 nm), electrons are ejected with a kinetic energy of 3.54×10-19 J.

What is the work function of the metal?
Chemistry
1 answer:
dsp733 years ago
8 0

We have that the work function of the metal

\phi=1.227*10^{-18}J

From the Question we are told that

UV radiation (λ = 162 nm)

Kinetic energy K.E =3.54*10-19 J.

Generally the equation for Kinetic energy    is mathematically given as

KE =\frac{hc}{\pi-\phi} \\\\\phi =\frac{ 6.626*10^{-34} * 3*10^8}{162*10^{-9} -3.54*10^{-19}}

\phi=1.227*10^{-18}J

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What is the mole fraction of HCl in a solution that contains 0.99 mole HCl and 3.6 mole H2O
marysya [2.9K]

Answer:

  0.216

Explanation:

The mole fraction of HCl is the number of moles of HCl (0.99) divided by the total number of moles in the solution.

  mole fraction = (0.99)/(0.99 +3.6) = 0.2157

The mole fraction of HCl is about 0.216.

4 0
3 years ago
How many moles are 5.55 x 102 atoms of Mg?<br> M2) an&gt; NU X 02.0
cupoosta [38]

Explanation:

number of atoms = moles × avegadro number

so 5.55 × 10^2 = moles × 6.023 × 10^23

moles = 5.55 × 10^2 ÷ 6.023 × 10^23 = 9.214×10−22 moles

4 0
2 years ago
How much heat energy is needed to raise the temperature of 59.7g of cadmium from 25°C to 100°C? The specific heat of cadmium is
Ilia_Sergeevich [38]
Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the change in temperature. It is expressed as: 

<span>Energy = mCΔT
</span><span>Energy = 59.7 (0.231) (100-25)
</span><span>Energy = 1034.30 J</span>
3 0
3 years ago
Ammonia is a principal nitrogen fertilizer. It is prepared by the reaction between hydrogen and nitrogen. 3H2(g) + N2(g) → 2NH3(
sergey [27]

Answer:

Explanation:

The equation of the reaction is given as:

             3H₂ + N₂ → 2NH₃

Given parameters:

Number of moles of NH₃ = 8moles

Number of moles of H₂ = ?

Number of moles of N₂ = ?

Solution

From the balanced reaction equation, we can establish some mole ratios that would help solve the problem:

 To find the number of moles of H₂;

      The equation shows that:

              2 moles of NH₃ were produced using 3 moles of H₂

therefore: 8 moles of NH₃ will be produced by  \frac{8 x 3}{2} = 12moles

So, 12 moles of hydrogen gas will react to give 8 moles of ammonia.

   To find the number of moles of N₂

 The equation shows that:

       2 moles of NH₃ were produced from 1 mole of N₂

      8 moles of NH₃ would be produced from  \frac{8 x 1}{2} = 4moles of Nitrogen gas

Therefore, 4moles of nitrogen gas would be produced

6 0
3 years ago
2NaOH+CO2-----&gt;Na2CO3+H2O
kondaur [170]

Answer:

13.2 g Na2CO3

Explanation:

Convert 10.0 g NaOH to mol.

10.0 g x 1 mol/39.997 g = 0.250 mol

Use mol ration given by the equation: 2 mol NaOH to 1 mol Na2CO3

0.250 mol NaOH x 1 mol Na2CO3/2 mol NaOH = 0.125 mol Na2CO3

Finally, convert the moles of Na2CO3 to grams.

0.125 mol Na2CO3 x 105.99 g/1 mol = 13.2 g

8 0
3 years ago
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