All categories

2 years ago

Help plsssssssssssssssssssssssssssssss

Mathematics

1 answer:

Akimi4 [234]2 years ago

3 0

Answer:

From smallest to greatest: -6, -3, 0, 1, 5

Step-by-step explanation:

The negative numbers will be on the left side of 0, and the positive numbers will be on the right side of 0.

You might be interested in

Carmen Martinez

klemol [59]

(4,4)
(10,7)

$\boxed{\sf Slope(m)=\dfrac{y_2-y_1}{x_2-x_1}}$

$\\ \sf\longmapsto m=\dfrac{7-4}{10-4}$

$\\ \sf\longmapsto m=\dfrac{3}{6}$

$\\ \sf\longmapsto m=\dfrac{1}{2}$

$\\ \sf\longmapsto m\approx0.5$

6 0

2 years ago

Read 2 more answers

9 X 5.000 = 9 x ____thousands

OverLord2011 [107]

Answer:

5x 1000

Step-by-step explanation:

4 0

2 years ago

A rectangular soccer field is 120 ft long by 64 ft wide. What dimensions would a scale drawing of the soccer field be if the fie

timofeeve [1]

Answer:

Hence dimension on drawing= 12 in by 6.4 in

Step-by-step explanation:

Actual dimension of the soccer field is 120 ft by 64 ft

Scale during drawing = 1in to 10 ft

Hence dimension on drawing = 120/10 by 64/10 = 12 in by 6.4 in

4 0

3 years ago

A quality control expert at LIFE batteries wants to test their new batteries. The design engineer claims they have a variance of

iris [78.8K]

Answer:

The probability that the mean battery life would be greater than 533.2 minutes (in a sample of 75 batteries) is $\\ P(z>0.48) = P(x>533.2) = 0.3156$

Step-by-step explanation:

The main thing we have to take into account in this question is that we are about to find the probability of a sample mean. The distribution for sample means follows a normal distribution with mean $\\ \mu$ and standard deviation $\\ \frac{\sigma}{\sqrt{n}}$ . Mathematically

$\\ \overline{x} \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

For values of the sample $\\ n \ge 30$ , no matter the distribution the data come from.

And the variable z follows a standard normal distribution, and, as we can remember, this distribution has a mean = 0 and a standard deviation = 1. Mathematically

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$ [1]

That is

$\\ z \sim N(0, 1)$

We have a variance of 3364. That is, a standard deviation of

$\\ \sigma^2 = 3364; \sigma = \sqrt{3364} = 58$

The population mean is

$\\ \mu = 530$

The sample size is $\\ n = 75$

The sample mean is $\\ \overline{x} = 533.2$

With all this information, we can solve the question

The probability that the mean battery life would be greater than 533.2 minutes

Using equation [1]

$\\ z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$\\ z = \frac{533.2 - 530}{\frac{58}{\sqrt{75}}}$

$\\ z = \frac{3.2}{\frac{58}{8.66025}}$

$\\ z = \frac{3.2}{6.69726}$

$\\ z = 0.47780$

With this value of z we can consult a cumulative standard normal table (or use some statistic program) to find the cumulative probability for z (and remember that this variable follows a standard normal distribution).

Most standard normal tables have values for z for only two decimals, so we can round the previous value for z as z = 0.48.

Then

$\\ P(z$

However, in the question we are asked for $\\ P(z>0.48) = P(x>533.2)$ . As well as all normal distributions, the standard normal distribution is symmetrical around the mean, and we have

$\\ P(z>0.48) = 1 - P(z$

Thus

$\\ P(z>0.48) = 1 - 0.68439$

$\\ P(z>0.48) = 0.31561$

Rounding to four decimal places, we have

$\\ P(z>0.48) = 0.3156$

So, the probability that the mean battery life would be greater than 533.2 minutes is (in a sample of 75 batteries) $\\ P(z>0.48) = P(x>533.2) = 0.3156$ .

5 0

3 years ago

Which of the following factors influences a consumer when deciding to buy a

OlgaM077 [116]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers