Answer:
Vapor pressure of solution is 78.2 Torr
Explanation:
This is solved by vapor pressure lowering:
ΔP = P° . Xm . i
Vapor pressure of pure solvent (P°) - vapor pressure of solution = P° . Xm . i
NaCl → Na⁺ + Cl⁻ i = 2
Let's determine the Xm (mole fraction) These are the moles of solute / total moles.
Total moles = moles of solvent + moles of solute
Total moles = 0.897 mol + 0.182 mol → 1.079 mol
0.182 / 1.079 = 0.168
Now we replace on the main formula:
118.1° Torr - P' = 118.1° Torr . 0.168 . 2
P' = - (118.1° Torr . 0.168 . 2 - 118.1 Torr)
P' = 78.2 Torr
Answer:
Ksp = 3.24 x 10⁻⁴
Explanation:
The dissociation equilibrium for a generic salt AB is:
AB(s) ⇄ A⁺(aq) + B⁻(aq)
s s
For instance, the expression for the Ksp constant is:
Ksp = [A⁺] [B⁻] = s x s = s²
According to the problem, 0.0180 mol of the salt is soluble in 1.00 L os water. That means that the solubility of the salt (s) is equal to 0.0180 mol per liter.
s = moles of solute/L of solution = 0.0180 mol/L
Thus, we calculate Ksp from the s value as follows:
Ksp = s² = (0.0180)² = 3.24 x 10⁻⁴
