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Sindrei [870]
1 year ago
9

A CHM 111 student completing Part B recorded the mass of several pieces of dry metal as

Chemistry
1 answer:
Leokris [45]1 year ago
4 0

The density of the metal in units of grams per milliliter is 11.31 g/mL

<h3>What is density? </h3>

The density of a substance is simply defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as

Density = mass / volume

<h3>How to determine the density of the metal </h3>

The following data were obtained from the question:

  • Mass of metal = 23.7412 g
  • Volume of water = 25 mL
  • Volume of water + metal = 27.1 mL
  • Volume of metal = 27.1 – 25 = 2.1 mL
  • Density of metal =?

Density = mass / volume

Density of metal = 23.7412 / 2.1

Density of metal = 11.31 g/mL

Learn more about density:

brainly.com/question/952755

#SPJ1

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Read 2 more answers
Concentrated hydrochloric acid is made by pumping hydrogen chloride gas into distilled water. If concentrated HCl contains 439 g
Elza [17]

Answer:

12.10 mol / 1 L

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity ( unit = mol / L or M )

V = volume of solution in liter ( unit = L ),  

n = moles of solute ( unit = mol ),  

Moles is denoted by given mass divided by the molecular mass ,  

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .  

From the question ,

The data given is as follows -

w = 439 g

As , we known for HCl ,

m = 36.46 g/mol

V = 1 L

From the above data ,

Moles are given as -

n = w / m

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M = n / V

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M = 12.10 mol /L

7 0
2 years ago
You are performing a titration of a triprotic acid, when you spill water on your lab notebook. you can read that: pka 1 = 1.40,
eimsori [14]
According to the PH formula:
PH= Pka +㏒ [strong base/weak acid]
when we have PH at the first equivalence =3.35 and the Pka1 = 1.4
So, by substitution, we can get the value of ㏒[strong base / weak acid]
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∴㏒[strong base/weak acid] = 3.35-1.4 = 1.95 
to get the Pka2 we will substitute with the value of ㏒[strong base/ weak acid] and the value of PH of the second equivalence point
∴Pk2 = PH2 - ㏒[strong base/ weak acid]
          = 7.55 - 1.95 = 5.6 
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3 years ago
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