Answer:
Density = 0.17 g/L
Explanation:
It is given that,
Volume of the inflated balloon filled with Helium,
Mass, m = 374 g
We need to find the density of helium. It is equal to its mass per unit volume. It can be given by :
d =m/V
So, the density of helium in the balloon is 0.17 g/L.
In the atom model, the poppy seeds are placed in different places to represent the different position of electrons.
The best way to know would be knowing what the electronic configuration of the element is. The electronic configuration of sulfur is 1s2 2p2 2p6 3s2 3p4. The p subshell can house a maximum of 6 electrons, but at this time it clutches 4 electrons, which means that sulfur has 2 unpaired electrons, both placed in the p-subshell. Or it could also be seen easily in the Lewis Dot Structure of Sulfur, you can see that there are two that has no pairs.
Mathematical formula of Ideal Gas Law is PV=nRT
where: P-pressure,
V-volume
n-number of moles; m/MW
T-Temperature
m-mass
d-density ; m/V
MW-Molecular Weight
R- Ideal Gas constant. If the units of P,V,n & T are atm, L, mol & K respectively, the value of R is 0.0821 L x atm / K x mol
Substituting the definitions to the original Gas equation becomes:
d= P x MW / (RxT)
Solution : d= .90atm x 28 g/mol (CO) / 0.0821Lxatm / mol x K x 323 K
d = 25.2 g / 26000 mL
d = .0.00096 g/mL is the density of CO under the new conditions