The horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m
<u>Explanation:</u>
Given:
h(x) = -0.026x² + 0.563x + 3
where,
h(x) is the height of the water
Initial speed, u = 14m/s
angle, θ = 30°
(a)
Horizontal distance = ?
h(x) = ax² + bx + c
the vertex is found at x = -b/2a
where,
x = distance to the maximum height
As compared to the equation given:
a = -0.026
b = 0.563
Thus,
Therefore, horizontal distance from the firefighter at which the maximum height of water occurs is 10.83m
Answer:
$2.44/gal
Explanation:
$58.56/24gallon/
Answer:
a. (x+5)^2 = 49
b. (x+7)^2 = (x+1)^2
Step-by-step explanation:
So the term "a number" is always going to be x. input x into the sentences. "X plus five, then squared, is forty-nine". when they do "is __", that means equal to. In the second question, seven more than x is x + 7 (the two numbers are interchangeable here). Equivalent also means equal. hope this helped :)
Answer:
a) distance covered by hare d1 = 8t
b) distance covered by tortoise d2 = 5t + 550
c) ∆d = 550 - 3t
Step-by-step explanation:
Given;
Speed of hare u = 8m/s
Speed of tortoise v = 5 m/s
Initial distance of tortoise d0 = 550 m
a) using the equation of motion;
distance covered = speed × time + initial distance
d = vt + d0
For hare;
d0 = 0
Substituting the values;
d1 = 8t + 0
d1 = 8t
b)using the equation of motion;
distance covered = speed × time + initial distance
d2 = vt + d0
For tortoise;
d0 = 550m
Substituting the values;
d2 = 5t + 550
d2 = 5t + 550 m
c) the number of meters the tortoise is ahead of the hare.
∆d = distance covered by tortoise - distance covered by hare
∆d = d2 - d1
Substituting the values;
∆d = (5t + 550) - 8t
∆d = 550 - 3t
