Ask question

Ask question

All categories

FromTheMoon [43]

4 years ago

7

What is the measure of

1 answer:

Tju [1.3M]4 years ago

5 0

Answer:

theory

Step-by-step explanation:

is the answer for your answer thank me

You might be interested in

Hurry Please! As you move to the _______ on a number line the values of the numbers _______. Which choice best completes the sen

Tanya [424]

Answer:

right; increase

4 0

3 years ago

Read 2 more answers

Which property of equality can be used to justify this step?

Aleonysh [2.5K]

C. Addition property of Equality

6 0

3 years ago

Read 2 more answers

Solve the word problem. Luke mowed a lawn today to earn some extra money. He spent $2.10 on fuel and $4.45 on lunch. He charged

Elis [28]

To solve this you must simply add $2.10 + $4.45 together to get a sum of $6.55. Next, you must subtract the $6.55 from $13.50 to get a difference/final solution of $6.95. So, in conclusion, Luke made a profit of $6.95 from mowing the lawn.

3 0

3 years ago

Read 2 more answers

NEED HELP ASAP!! WILL MARK BRAINLIEST TO THE RIGHT ANSWER!!

Usimov [2.4K]

For the first one :) x + 6, y - 10

6 0

3 years ago

A student takes a multiple-choice test that has 11 questions. Each question has five choices. The student guesses randomly at ea

marissa [1.9K]

Answer:

a) P(6) = 0.0097

b) P(More than 3) = 0.1611

Step-by-step explanation:

For each question, there are only two possible outcomes. Either it is guessed correctly, or it is not. Questions are independent of each other. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A student takes a multiple-choice test that has 11 questions.

This means that $n = 11$

Each question has five choices.

This means that $p = \frac{1}{5} = 0.2$

(a) Find P (6)

This is P(X = 6).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 6) = C_{11,6}.(0.2)^{6}.(0.8)^{5} = 0.0097$

P(6) = 0.0097

(b) Find P (More than 3).

Either P is 3 or less, or it is more than three. The sum of the probabilities of these outcomes is 1. So

$P(X \leq 3) + P(X > 3) = 1$

We want P(X > 3). So

$P(X > 3) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{11,0}.(0.2)^{0}.(0.8)^{11} = 0.0859$

$P(X = 1) = C_{11,1}.(0.2)^{1}.(0.8)^{10} = 0.2362$

$P(X = 2) = C_{11,2}.(0.2)^{2}.(0.8)^{9} = 0.2953$

$P(X = 3) = C_{11,3}.(0.2)^{3}.(0.8)^{8} = 0.2215$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0859 + 0.2362 + 0.2953 + 0.2215 = 0.8389$

Then

$P(X > 3) = 1 - P(X \leq 3) = 1 - 0.8389 = 0.1611$

P(More than 3) = 0.1611

8 0

4 years ago