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vfiekz [6]
3 years ago
9

C=5/9(F-32) help please

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0
C=2/5 with syptolis thereon so 2/5(C5/9) is the abswer for C (F-32)= hypoteticulos syptolis F-25/32(-32/35) this the answer for (F-32)
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The length of the hypotenuse of a right angled triangle exceeds the length of the base by 2cm and exceeds twice the length of th
insens350 [35]

Answer: a = 8;  b = 15;  c = 17

Step-by-step explanation:

c = b + 2  and c = 2a + 1

b = c − 2 and a =  \frac{c-1}{2}

​

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If c = 1 then b = 1 - 2 = -1, that's not possible

So x = 17

b = 17 - 2 = 15

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Length sides of the triangle are 17 cm, 15 cm and 8 cm.

I saw some of this on a site but I want to make sure its correct so we're gonna apply the pythagorean theory and see if its correct.

a^{2} + b^{2} = c^{2} \\8^{2} + 15^{2} = 17^{2} \\64 + 225 = 289\\289 = 289\\

This shows that this is correct.

Hope this helped! Again, some of this was from a site, not from me.

3 0
3 years ago
What are the solutions to the equation x² = 256?
tester [92]
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Are these answers correct
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