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vfiekz [6]
3 years ago
9

C=5/9(F-32) help please

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0
C=2/5 with syptolis thereon so 2/5(C5/9) is the abswer for C (F-32)= hypoteticulos syptolis F-25/32(-32/35) this the answer for (F-32)
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The square root of a number is 2k. what is half of the number?​
hammer [34]

2k isuwgqjaiqu2yquqi

8 0
3 years ago
A room that is 5 meters long has an area
Sveta_85 [38]

Answer:

Breadth=x+2

Step-by-step explanation:

Solution,\\\\Length(l)=5m\\\\Area=5x+10m^{2} \\\\Breadth(b)=?\\\\As,\\\\Area=l*b\\\\5x+10=5*b\\\\b=\frac{5x+10}{5}\\\\b=\frac{5x}{5} +\frac{10}{5} \\\\b=x+2

7 0
2 years ago
The hypotenuse of a right triangle is 45 inches,which one of the sides being 18 inches. Find the midding side length. Round to t
bagirrra123 [75]

Answer:

The length of the missing side is 41.24 inches

Step-by-step explanation:

* Lets talk about the Pythagoras theorem

- It used in the right angle triangle

- The hypotenuse is the opposite side to the right angle and it's the

  longest side in the triangle

- The two other sides in the right angle triangle are the legs of

 the right angle

- If the length of the hypotenuse is c units and the lengths of the

 two legs of the right angle area a and b

∴ a² + b² = c² ⇒ c = √(a² + b²)

* Now lets solve the problem

∵ The length of the hypotenuse = 45 inches

∵ The length of one legs of the right angle = 18 inches

- Lets use the Pythagoras theorem

∴ c² = a² + b²

∴ 45² = 18² + b² ⇒ subtract 18² from both sides

∴ b² = 45² - 18² = 2025 - 324 = 1701 ⇒ take square root for both sides

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8 0
3 years ago
Read 2 more answers
Can someone plz help me solved this problem! I’m giving you 10 points! I need help plz help me! Will mark you as brainiest!
sergeinik [125]

Answer:

a). 8(x + a)

b). 8(h + 2x)

Step-by-step explanation:

a). Given function is, f(x) = 8x²

    For x = a,

    f(a) = 8a²

    Now substitute these values in the expression,

    \frac{f(x)-f(a)}{x-a} = \frac{8x^2-8a^2}{x-a}

                  = \frac{8(x^2-a^2)}{(x-a)}

                  = \frac{8(x-a)(x+a)}{(x-a)}

                  = 8(x + a)

b). \frac{f(x+h)-f(x)}{h} = \frac{8(x+h)^2-8x^2}{h}

                      = \frac{8(x^2+h^2+2xh)-8x^2}{h}

                      = \frac{8x^2+8h^2+16xh-8x^2}{h}

                      = (8h + 16x)

                      = 8(h + 2x)

4 0
3 years ago
Solve equation <br> 9x^2+7x=3
Nonamiya [84]

I’m not for sure but if I had to guess I would say 115

3 0
3 years ago
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