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mart [117]
3 years ago
12

Is burning sugar a chemical or physical change? Please provide explanation

Chemistry
2 answers:
solong [7]3 years ago
6 0

Answer:

It is a chemical change

Explanation:

the reason is because the will not be able to materialize back into it's original form.

Umnica [9.8K]3 years ago
6 0
It be a chemical change my dude
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Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
Can someone please help I need help?!?!
anzhelika [568]

Answer:

a: 6 moles

b: 6.75 moles

c: 5 grams

Explanation:

a: mole ratio 2:3

b: mole ratio 2:3

c: mole ratio 2:2

7 0
3 years ago
Science 6th grade please help me :)
Gnom [1K]
I’m pretty sure the answer is D :)
6 0
3 years ago
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Chemistry Question! 20 Points!
Delvig [45]

Answer:

A

Explanation:

I guess it's a, because nuclear decay is likely to occur when either the mass or atomic number is greater than 83.

7 0
3 years ago
If the initial velocity of the car in the previous problem (the car accelerates at 5.00 km/hr/s for 3.50 sec) is 22.6 km/hr, wha
MatroZZZ [7]
40.10 km/hr I believe.
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3 years ago
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