All categories

3 years ago

A sample of sulfuryl fluoride, SO2F2, has a mass of 19.2 g. What amount, in moles, does this mass represent?

Chemistry

2 answers:

Rzqust [24]3 years ago

8 0

Answer:

0.188 moles.

Explanation:

Molar mass of SO2F2

= 32 + 2*16 + 2 * 19

= 102 g.

So 19.2g = 19.2 / 102

= 0.188 moles.

snow_tiger [21]3 years ago

5 0

Answer:

0.188 moles

Explanation:

moles=mass/molar mass

moles= 19.2/ (32+32+38)

moles= 0.188

You might be interested in

The compound methyl butanoate smells like apples. Its percent composition is 58.8% C, 9.9% H, and 31.4% O. What’s the empirical

blsea [12.9K]

To find the empirical formula you would first need to find the moles of each element:

58.8g/ 12.0g = 4.9 mol C

9.9g/ 1.0g = 9.9 mol H

31.4g/ 16.0g = 1.96 O

Then you divide by the smallest number of moles of each:

4.9/1.96 = 2.5

9.9/1.96 = 6

1.96/1.96 = 1

Since there is 2.5, you find the least number that makes each moles a whole number which is 2.

So the empirical formula is C5H12O2.

6 0

3 years ago

6. The modern view of the atom has come a long way from that of a solid, indestructible sphere

Fynjy0 [20]

It is a true statement

4 0

3 years ago

If 81g of water is measured out, how many moles are in the sample? *

valkas [14]

Answer:

Explanation:

because moles = mass /mr

so 81/18(mr of H2O=2+16)

moles =4.5

hope this helps:)

7 0

3 years ago

If expending 3500 kcal is equal to a loss of 1.0 lb, how many days will it take Charles to lose 5.0 lb? Express your answer to t

Trava [24]

Answer:

WAIT

good luck on whatever this is for my dude.

3 0

3 years ago

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low

LenaWriter [7]

Answer:

Compound B has greater molar mass.

Explanation:

The depression in freezing point is given by ;

$\Delta T_f=i\times k_f\times m$ ..[1]

$m=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Mass of solvent in kg}}$

Where:

i = van't Hoff factor

$k_f$ = Molal depression constant

m = molality of the solution

According to question , solution with 5.00 g of A in 100.0 grams of water froze at at lower temperature than solution with 5.00 g of B in 100.0 grams of water.

The depression in freezing point of solution with A solute: $\Delta T_{f,A}$