Answer:
Tanaysha replace 8 by ( 10 -2) to solve the given expression.
Step-by-step explanation:
Here, the given expression to be solved is:
72 - 8 .......... (1)
Now, as we know: 8 = 10 - 2
Replacing the value of 8 with ( 10 - 2), we get:
72 - 8
= 72 - (10 - 2)
= 72 - 10 + 2
= (72 + 2 ) - 10
Now, adding ( 72 ) and ( 2) , we get:
= 74 - 10
Subtracting 10 from 74, we get:
= 64
So, Tanaysha replace 8 by ( 10 -2) to solve the given expression.
Answer:
I can't include a picture but it will be the same shape except it will be flipped over and will look a bit like differently angled packman with the back of the mouth apart the same distance, with the mouth "pointier" part of it one line away from the red line from the other side.... Oof sorry if this didn't help, I tried my best...
Step-by-step explanation:
From the "point" of the blue triangle, go diagonally SE 2 spaces. From there, draw a straight line to the right for 3 spaces. From there, draw upwards two spaces, and then connect those two lines into a triangle.
Soo lets take anna=2a sun=2a and amanda=a
2a+2a+a=45
5a=45
a=45/5
a=9
then anna and sun=18 and amanda=9
and if we compare the diff annas dollars from attachment and the work shown above = 18-15=3
soo the answer should be three
Answer: d. None of the above are correct.
Step-by-step explanation: Noise is a superfluous random alteration in an eletrical signal. There are different types of noises created by different devices and process. Thermal noise is one of them. It is unavoidable because is created by the agitation of the charge carriers, due to temperature, inside an eletrical conductor at equilibrium and is present in all eletrical circuits.
The formula to find the thermal noise power (N) is: N = .T.B, where:
is Boltzmann constant (1.38.J/K);
T is temperature in Kelvin;
B is the bandwith;
Calculating the thermal noise power:
N = 1.38.·292·40
N = 16118.4. dBm
The thermal noise power [N] = 16118.4. dBm
Noise power density or simply Noise density (N₀) is the noise power per unit of bandwith and its SI is watts per hertz.
For thermal noise, N₀ = kT, where
<em>k </em>is the Boltzmann constant in J/K;
T is the receiver system noise temperature in K;
N₀ = 1.38. . 292
N₀ = 402.96. W/Hz
The thermal noise power density [N₀] = 402.96. W/Hz
Judging by the question you have provided I came to the conclusion that you have already solved your own problem!
If the goal is to find X when X=-15 then your answer for X should be -15!
If this is not the entire equation please post the entire one!
Hope this helped!
-Blake