Answer:
None of these.
Step-by-step explanation:
Let's assume we are trying to figure out if (x-6) is a factor. We got the quotient (x^2+6) and the remainder 13 according to the problem. So we know (x-6) is not a factor because the remainder wasn't zero.
Let's assume we are trying to figure out if (x^2+6) is a factor. The quotient is (x-6) and the remainder is 13 according to the problem. So we know (x^2+6) is not a factor because the remainder wasn't zero.
In order for 13 to be a factor of P, all the terms of P must be divisible by 13. That just means you can reduce it to a form that is not a fraction.
If we look at the first term x^3 and we divide it by 13 we get 
we cannot reduce it so it is not a fraction so 13 is not a factor of P
None of these is the right option.
Y = mx + b
slope(m) = -2/3
(2,-5)...x = 2 and y = -5
now we sub, we r looking for b, the y int
-5 = -2/3(2) + b
-5 = - 4/3 + b
-5 + 4/3 = b
- 15/3 + 4/3 = b
- 11/3 = b
equation is : y = -2/3x - 11/3...but we need it in standard form
Ax + By = C
y = -2/3x - 11/3
2/3x + y = - 11/3....multiply by 3
2x + 3y = -11 <== standard form
Answer:
the second description and and expression is correct
Step-by-step explanation:
the first one is wrong because it says 7 minus while it should be minus 7
No it isn't.
Explanation:
x/y * y = (y-6) * y
x = y^2 - 6y
A function gives just one y for every x
In this case there will always be 2 y's for every x
Example:
y can be
y = 6
or
y =−6
(0,-6) & (0,6)
