3 years ago

If 9 babies are randomly selected, how many different gender sequences are possible?

Mathematics

1 answer:

e-lub [12.9K]3 years ago

7 0

2^9=512

There are 512 possible solutions

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Solve 5,4 = n/-0.9

PtichkaEL [24]

Step-by-step explanation:

5.4×-0.9=n

n=-4.86

(-4/5)/(1/3)=x

X=-2 2/5

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3 years ago

Fractional form of 0.8

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Answer:

8/10

Step-by-step explanation:

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A class is made up of 10 boys and 5 girls. Half of the boys wear glasses. A student is selected at random from this class. What

saveliy_v [14]

Answer:

1/3

Step-by-step explanation:

Of the 15 students in the class, 5 are boys with glasses. The probability of selecting one at random is 5/15 = 1/3.

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Solve the absolute value inequality: [X + 12[ +5 <27

Westkost [7]

Answer:

Option C.

Step-by-step explanation:

The given absolute value inequality is

$|x+12|+5$

Isolate the absolute value by subtracting 5 from both sides.

$|x+12|+5-5$

$|x+12|+0$

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Therefore, the correct option is C.

We can further solve this, to find the solution of the given inequality.

$-22$

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$-22-12$

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The solution of given inequality is $-34$ .

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