Answer:
this:name = 'John'
print("Is name == 'John'? I predict True.")
print(name == 'John')
print("\nIs name == 'Joy'? I predict False.")
print(car == 'Joy')
this:age = '28'
print("Is age == '28'? I predict True.")
print(age == '28')
print("\nIs age == '27'? I predict False.")
print(age == '27')
this:sex = 'Male'
print("Is sex == 'Female'? I predict True.")
print(sex == 'Female')
print("\nIs sex == 'Female'? I predict False.")
print(sex == 'Joy')
this:level = 'College'
print("Is level == 'High School'? I predict True.")
print(level == 'High School')
print("\nIs level == 'College'? I predict False.")
print(age == 'College')
Conditions 1 and 2 test for name and age
Both conditions are true
Hence, true values are returned
Conditions 3 and 4 tests for sex and level
Both conditions are false
Hence, false values are returned.
Answer:
In the time complexity, the array-list can easily be accessible any type of element in the the given list in the fixed amount of time.
On the other hand, the linked list basically require that the list must be traversed from one position to another end position.
The Array-List can get to any component of the rundown in a similar measure of time if the file value is know, while the Linked-List requires the rundown to be crossed from one end or the other to arrive at a position.
Answer:
D) ["Kathy Bones", "Jill Brewer", "Joe Schnook", "Tom Smith"]
Explanation:
The context of the problem explains a computer program that sorts names in "ascending order" (A to Z) since the ASCII table has capital A start a lower number and it increases from there to capital Z.
Notice how the attached file, which is a portion of the ASCII table, shows that letters after A are also higher in decimal value than the previous letter.
With this in mind, we know that all this program does is sort by last name alphabetical order. From there, just sort the given names using that same criteria, last name alphabetical order, and the correct answer is determined.
<em>Please put "Brainliest" on my answer if it helped you out!</em>
<em>If you want to learn more about this subject, you can search:</em>
<em>- ASCII Table</em>
<em>- Lists in Programming</em>
<em>- Sorting Procedures</em>
Answer:
import java.util.Scanner;
public class DashLine {
public static void main(String[] args) {
// Declaring variables
int n;
/*
* Creating an Scanner class object which is used to get the inputs
* entered by the user
*/
Scanner sc = new Scanner(System.in);
// Getting the input entered by the user
System.out.print("Enter a number :");
n = sc.nextInt();
// calling the method by passing the user entered input as argument
dashedLine(n);
}
//This method will print the dashed line for number greater than zer
private static void dashedLine(int n) {
if (n > 0) {
for (int i = 1; i <= n; i++) {
System.out.print("-");
}
System.out.println();
}
}
}
Explanation:
