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nydimaria [60]
3 years ago
10

What kind of energy is stored in an electromagnet?

Chemistry
1 answer:
meriva3 years ago
6 0
Kinetic is the answer to your question
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Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. Solutes formula hydroch
matrenka [14]

Compounds which on dissolving in water gets completely dissociates into its ions are known as strong electrolytes whereas compounds which on dissolving in water gets partially dissociates into its ions are known as weak electrolytes.


Substances which gives solution on dissolving in water and do not dissociates into ions also does not conduct electric current are known as nonelectrolyte.

  • Hydrochloric acid, HCl

On adding HCl (strong acid) in water, it will completely dissociates into ions (H^{+} and Cl^{-}) and thus, it is a strong electrolyte.

  • Sodium hydroxide, NaOH

On adding NaOH (strong base) in water, it will completely dissociates into ions (Na^{+} and  OH^{-}) and thus, it is a strong electrolyte.

  • Formic acid, HCOOH

On adding HCOOH (weak acid) in water, it will partially dissociates into ions (H^{+} and  HCOO^{-}) and thus, it is a weak electrolyte.

  • Methyl amine, CH_3NH_2

On adding CH_3NH_2 (weak base) in water, it will partially dissociates into ions (CH_3NH_3^{+} and  OH^{-}) and thus, it is a weak electrolyte.

  • Potassium chloride, KCl

On adding KCl in water, it will completely dissociates into ions (K^{+} and  Cl^{-}) and thus, it is a strong electrolyte.

  • Ethanol, C_2H_5OH

On adding C_2H_5OH in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

  • Sucrose, C_{12}H_{22}O_{11}

On adding C_{12}H_{22}O_{11} in water, it will not dissociates into ions  and thus, it is a nonelectrolyte.

3 0
3 years ago
About one hundred thousand years ago, very fluid lava started erupting slowly and gently from a place near a plate boundary. Wha
victus00 [196]

a is the answer because all of the other answers are wrtong

3 0
3 years ago
What would be the total volume of the new solution when it is changed from 0.2 M to 0.04 M?
34kurt
The question is incomplete.

You need two additional data:

1) the original volume
2) what solution you added to change the volume.

This is a molarity problem, so remember molarity definition and formula:

M = n / V in liters: number of moles per liter of solution

To give you the key to answer this kind of questions, supppose the original volumen was 1 ml and that you added only water (solvent).

The original solution was:

V= 1 ml
M = 0.2 M

Using the formula for molarity, M = n / V

n = M×V = 0.2 M × (1 / 10000)l = 0.0002 moles

For the final solution:

n = 0.0002 moles
M = 0.04

From M = n / V ⇒ V = n / M = 0.002 moles / 0.04 M = 0.05 l

Change to ml ⇒ 0.05 l × 1000 ml / l = 50 ml.  This would be the answer for the hypothetical problem that I assumed for you.

I hope this gives you all the cues you need to answer similar problems about molarity.
6 0
3 years ago
Read 2 more answers
Is liquid ammonia a household acid?​
alexgriva [62]

Yes it is an cleaning product

8 0
3 years ago
Read 2 more answers
When a Na atom loses an electron to a Cl atom, the two atoms have opposite charges and are attracted to one another. What is the
ahrayia [7]

Answer:

Ionic bond

Explanation:

When Na loses an electron, it becomes positive ion.  

When Cl gains  an electron, it becomes negative ion.  

The electrostatic attraction between these ions is an ionic bond.

7 0
3 years ago
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