Compound a has a pka of 7 and compound b has a pka of 10. compound a is how many times more acidic than compound b?
2 answers:
Compound A is 1000 times more acidic than compound B
<h3>Further explanation</h3>The pKa value is an indicator of the strength of an acid
The pKa is a logarithmic function. pKa is the negative logarithm to the base ten of Ka
pKa = - log Ka
The smaller the pKa, the stronger the acid
A difference of 1 pKa shows a difference of 10 times in the acidity
Suppose there is a difference of 3 pKa units, then corresponds to a 10³ difference in acidity
Compound A has a pKa of 7 and compound B has a pKa of 10.
Because the value of pKa compound A is smaller than compound B, compound A is more acidic than compound B
Ka value of each compound:
- compound A
pKa = 7
pKa = - log Ka
7 = - log Ka
Ka = 10⁻⁷
- compound B
pKa = 10
pKa = - log Ka
10 = - log Ka
Ka = 10⁻¹⁰
So that the difference in acidity
10⁻⁷ / 10¹⁰ = 10³ = 1000 times
<h3>Learn more</h3>The pH scale is a measurement system
the ka reaction of hcn
strong enough acids to react almost completely with a hydroxide ion
Keywords: pKa, strong acid, logarithmic function, compound
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From the given information:
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Recall that; the equilibrium constant for the reaction = 0.8325;
If we want to find:
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Answer:
pH
Explanation:
For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.
pH
Substituting the available values in above equation, we can say that the pH of the solution is equal to
pH
pH of a M HCL solution