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GuDViN [60]
4 years ago
11

Compound a has a pka of 7 and compound b has a pka of 10. compound a is how many times more acidic than compound b?

Chemistry
2 answers:
Pavel [41]4 years ago
4 0
Ka is the acid dissociation equilibrium constant. The larger the value of the Ka, the stronger is the acid. To find Ka from pKa, the equation is:

pKa = -log[Ka]

@pKa = 7
7 = -log[Ka]
Ka = 1×10⁻⁷

@pKa = 10
10 = -log[Ka]
Ka = 1×10⁻¹⁰

This, pKa 7 is more acidic than pKa 10. The scale factor would be:
1×10⁻⁷/1×10⁻¹⁰ = 1,000

<em>Therefore, Compound A is 1,000 times more acidic than Compound B.</em>

oksian1 [2.3K]4 years ago
3 0

Compound A is 1000 times more acidic than compound B

<h3>Further explanation</h3>

The pKa value is an indicator of the strength of an acid

The pKa is a logarithmic function. pKa is the negative logarithm to the base ten of Ka

pKa = - log Ka

The smaller the pKa, the stronger the acid

A difference of 1 pKa shows a difference of 10 times in the acidity

Suppose there is a difference of 3 pKa units, then corresponds to a 10³ difference in acidity

Compound A has a pKa of 7 and compound B has a pKa of 10.

Because the value of pKa compound A is smaller than compound B, compound A is more acidic than compound B

Ka value of each compound:

  • compound A

pKa = 7

pKa = - log Ka

7 = - log Ka

Ka = 10⁻⁷

  • compound B

pKa = 10

pKa = - log Ka

10 = - log Ka

Ka = 10⁻¹⁰

So that the difference in acidity

10⁻⁷ / 10¹⁰ = 10³ = 1000 times

<h3>Learn more</h3>

The pH scale is a measurement system

brainly.com/question/599764

the ka reaction of hcn

brainly.com/question/9012584

strong enough acids to react almost completely with a hydroxide ion

brainly.com/question/5273689

Keywords: pKa, strong acid, logarithmic function, compound

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Be sure to answer all parts. Write the balanced equations corresponding to the following rate expressions: a) rate = − 1 3 Δ[CH4
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Answer : The balanced equations will be:

(a) 3CH_4+2H_2O+CO_2\rightarrow 4CH_3OH

(b) 2N_2O_5\rightarrow 2N_2+5O_2

(c) 2H_2+2CO_2+O_2\rightarrow 2H_2CO_3

Explanation :

The general rate of reaction is,

aA+bB\rightarrow cC+dD

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}

\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}

\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}

\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}

Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

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