All categories

3 years ago

Compound a has a pka of 7 and compound b has a pka of 10. compound a is how many times more acidic than compound b?

Chemistry

2 answers:

Pavel [41]3 years ago

4 0

Ka is the acid dissociation equilibrium constant. The larger the value of the Ka, the stronger is the acid. To find Ka from pKa, the equation is:

pKa = -log[Ka]

@pKa = 7
7 = -log[Ka]
Ka = 1×10⁻⁷

@pKa = 10
10 = -log[Ka]
Ka = 1×10⁻¹⁰

This, pKa 7 is more acidic than pKa 10. The scale factor would be:
1×10⁻⁷/1×10⁻¹⁰ = 1,000

<em>Therefore, Compound A is 1,000 times more acidic than Compound B.</em>

oksian1 [2.3K]3 years ago

3 0

Compound A is 1000 times more acidic than compound B

<h3>Further explanation</h3>

The pKa value is an indicator of the strength of an acid

The pKa is a logarithmic function. pKa is the negative logarithm to the base ten of Ka

pKa = - log Ka

The smaller the pKa, the stronger the acid

A difference of 1 pKa shows a difference of 10 times in the acidity

Suppose there is a difference of 3 pKa units, then corresponds to a 10³ difference in acidity

Compound A has a pKa of 7 and compound B has a pKa of 10.

Because the value of pKa compound A is smaller than compound B, compound A is more acidic than compound B

Ka value of each compound:

compound A

pKa = 7

pKa = - log Ka

7 = - log Ka

Ka = 10⁻⁷

compound B

pKa = 10

pKa = - log Ka

10 = - log Ka

Ka = 10⁻¹⁰

So that the difference in acidity

10⁻⁷ / 10¹⁰ = 10³ = 1000 times

<h3>Learn more</h3>

The pH scale is a measurement system

brainly.com/question/599764

the ka reaction of hcn

brainly.com/question/9012584

strong enough acids to react almost completely with a hydroxide ion

brainly.com/question/5273689

Keywords: pKa, strong acid, logarithmic function, compound

You might be interested in

The proposed mechanism for a reaction is: Step 1: A + B X (fast) Step 2: X + C Y (slow) Step 3: Y D (fast) What is the overall r

PolarNik [594]

Answer:

(slow)xy2+z→xy2z (fast) c step1:step2:xy2+z2→xy2z2

Explanation:

Step1: xy2+z2→xy2z2 (slow)

Step2: xy2z2→xy2z+z (fast)

2XY 2 + Z 2 → 2XY 2 Z

Rate= k[xy2][z2]

When the two elementary steps are summed up, the result is equivalent to the stoichiometric equation. Hence, this mechanism is acceptable. The order of both elementary steps is 2, which is ‘≤3’; this also makes this mechanism acceptable. Furthermore, the rate equation aligns with the experimentally determined rate equation, and this also makes this mechanism acceptable. Therefore, since all the three rules have been observed, this mechanism is possible.

5 0

3 years ago

If the mass of a material is 78 grams and the volume of the material is 23 cm3, what would the density of the material be?

Paraphin [41]

Density = mass / volume

Density = (78g) / (23cm^3)

Density = 3.4g/cm^3

8 0

3 years ago

Read 2 more answers

Convert 7.72 years into days.

Lelu [443]

Answer:2817.8

Explanation:multiply the value by 365

4 0

3 years ago

Read 2 more answers

Name at least four other gases in the atmosphere besides oxygen and nitrogen

nikitadnepr [17]

Carbon dioxide (CO2)
Argon (Ar)
Hydrogen (H)
Helium (He)

8 0

3 years ago

A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl

diamong [38]

Answer:

$\large \boxed{\text{98 m$\cdot$s}^{-2}}$

Explanation:

The formula for the velocity of the ball is

$v = \sqrt{2gh}$

1. Velocity at time of impact

$v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}$

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

$v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}$

3. Acceleration

$a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}$

5 0

3 years ago