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Olegator [25]
3 years ago
13

The strength of a magnetic field follows _____.

Chemistry
2 answers:
Solnce55 [7]3 years ago
8 0

Answer: The correct answer is "law of poles".

Explanation:

Magnetic field lines are the area around the magnet in which the magnetic force can be experienced.

Law of poles: Like poles of the magnets repel each other with the magnetic force of repulsion. Unlike poles of the magnets attract each other with the magnetic force of attraction.

The direction of the magnetic field lines is from north pole to south pole. The strength of the magnetic field varies with the distance from the poles.

The strength of the magnetic field is stronger at the poles. It decreases from the poles.

The strength of the magnetic field does not follow an inverse square law. The gravity field and the electric field follow an inverse square law. The force from the magnet decreases faster than an inverse square law because all magnets have two opposite poles.

The strength of a magnetic field follows law of poles.

Therefore, the correct option is (D).

nordsb [41]3 years ago
5 0

d is correct answer

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The answer will be 25.92 L for 17.0 c
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A hypothetical main group element E reacts with chlorine to form an ionic compound with the formula ECl. The element is a member
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3 years ago
The absorbance of an equilibrium mixture containing FeSCN2 was measured at 447 nm and found to be 0.347. What is the equilibrium
Ksenya-84 [330]

Answer:

The concentration is C = 1.11 mol/L

Explanation:

From the question we are told that

     The absorbance is  A = 0.347

       The length is  l =  447 nm  =  447 *10^{-7} \ cm

     

Generally absorbance is mathematically represented as

        A =  \epsilon*  C * l

where \epsilon is the molar absorptivity of  FeSCN2  with a value \epsilon  =  7.0*10^3 L/cm/mol

 and  C is the equilibrium concentration of FeSCN2

So  

       C = \frac{A}{\epsilon *  l  }

substituting values

        C = \frac{0.347}{7.0*10^{3} *  447 *10^{-7}  }

         C = 1.11 mol/L

5 0
3 years ago
The reaction of hydrogen and iodine to produce hydrogen iodide has a Kc of 54.3 at 703 K. Given the initial concentrations of H2
pentagon [3]

Answer:

[HI] = 0.7126 M

Explanation:

Step 1: Data given

Kc = 54.3

Temperature = 703 K

Initial concentration of H2 and I2 = 0.453 M

Step 2: the balanced equation

H2 + I2 ⇆ 2HI

Step 3: The initial concentration

[H2] = 0.453 M

[I2] = 0.453 M

[HI] = 0 M

Step 4: The concentration at equilibrium

[H2] = 0.453 - X

[I2] = 0.453 - X

[HI] = 2X

Step 5: Calculate Kc

Kc = [Hi]² / [H2][I2]

54.3 = 4x² / (0.453 - X(0.453-X)

X = 0.3563

[H2] = 0.453 - 0.3563 = 0.0967 M

[I2] = 0.453 - 0.3563 = 0.0967 M

[HI] = 2X = 2*0.3563 = 0.7126 M

3 0
3 years ago
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