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olasank [31]
3 years ago
8

Sediment layers stop lateral spreading when:

Chemistry
1 answer:
Xelga [282]3 years ago
7 0

Answer:

Peepee poopoo!

Explanation:

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Help me answer this question pls
Anarel [89]
Electrical energy !! i hope this helped :))
5 0
3 years ago
Which are forms of frozen water? Check all that apply. dew frost hail rain sleet
MariettaO [177]

When moist air cools below its dew point on a cold surface it forms dew. It is in the liquid state.

Rain is again a form of precipitation in which water is in the liquid state.

When air temperature is below freezing, the precipitation that results is referred to as frost. Hail is a form of precipitation in the ice balls whereas as sleet is a mixture of rain and snow.

Ans: Forms of frozen water- frost, hail and sleet

7 0
3 years ago
Read 2 more answers
Calculate the number of grams in 4.56 x 1026 atoms of sodium phosphate. Be sure to balance the charges of sodium phosphate. Help
zalisa [80]

Answer:

124225.91 g of Na₃PO₄

Explanation:

From the question given above, the following data were obtained:

Number of atoms of Na₃PO₄ = 4.56×10²⁶ atoms

Mass of Na₃PO₄ =?

From Avogadro's hypothesis,

6.02×10²³ atoms = 1 mole of Na₃PO₄

Next, we shall determine the mass of 1 mole of Na₃PO₄. This can be obtained as follow:

1 mole of Na₃PO₄ = (23×3) + 31 + (16×4)

= 69 + 31 + 64

= 164 g

Thus,

6.02×10²³ atoms = 164 g of Na₃PO₄

Finally, we shall determine the mass of Na₃PO₄ that contains 4.56×10²⁶ atoms. This can be obtained as follow:

6.02×10²³ atoms = 164 g of Na₃PO₄

Therefore,

4.56×10²⁶ atoms = (4.56×10²⁶ × 164)/6.02×10²³

4.56×10²⁶ atoms = 124225.91 g of Na₃PO₄

Therefore, 124225.91 g of Na₃PO₄ contains 4.56×10²⁶ atoms

4 0
2 years ago
You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that
Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

                                     = B ml x 1.0 g/ml

                                     = B g

Amount of NaOCl in this stock solution = 5% of B g

                                     = \frac{5}{100} x B g

                                     = 0.05 B g

Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

                        = 0.005 g

B = \frac{0.005}{0.05}

  = 0.1

Thus 0.1 ml of bleach should be added to each liter of test solution.

4 0
3 years ago
The chemical equation below shows the reaction of glucose and oxygen.
goldfiish [28.3K]
• Aerobic respiration, photosynthesis


It is aerobic because it requires oxygen to be carried out. Anaerobic on the other hand does not require oxygen.

It’s two products would be the reactants for photosynthesis because in photosynthesis the reverse reaction takes place as glucose is produced along with water from carbon dioxide (CO2) and water (H2O) in the presence of chlorophyll and sunlight.
7 0
3 years ago
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