Answer:
The first part of the question is asking about BUOYANT FORCE or UPTHRUST.
Upthrust =TRUE WEIGHT-APPARENT WEIGHT
TRUE WEIGHT=mg
TRUE weight=50kg×10m/s²
=500N
upthrust=500N-380N
FB=120N
volume of the rock=mass/density.
since the granite is completely submerged, the volume of the displaced liquid will be equal to the volume of the body.
upthrust=Vdg
120N=V×1000kg/m³×10m/s²
120N=V×10000kg/m²s²
120/10000=V
v=0.012m³
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If the width of the slit is increased by a factor of two , then the central maxima will get decreased by half.
since , width of the central maxima is inversely proportional to the width of the slit . Which implies if width of the slit get increased then width of the central maxima will get decreased and vice versa.
central maxima = (2 * wavelength * D) / width of the slit
= (2 * lambda * D) / d
if initially width of the slit = d
then, after increasing it by a factor of two it become = 2d
central maxima = (2 * lambda * D) / 2d
= (lambda * D) / d
If the width of the slit is increased by a factor of two , then the central maxima will get decreased by half.
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