Using Placks’s constant and frequency
<span>Anger is to angry as fire is to blazing. </span>
Advantage equals 0.1, mate
1) advantage of plane: 5 divided by 25 = 0.2
2) advantage of fixed pulleys = 0
3) advantage of movable pulley = 0.5
4) and you multiply 0.2 and 0.5 = 0.1
to lift 1kg you don't need force 10N, you will just need 1N
Answer:
A torque of 102.5375 Nm must be exerted by the fireman
Explanation:
Given:
The rate of water flow = 6.31 kg/s
The speed of nozzle = 12.5 m/s
Now, from the Newton's second law we have
The reaction force to water being redirected horizontally (F) = rate of change of water's momentum in the horizontal direction
thus we have,
F = 6.31 kg/s x 12.5m/s
or
F = 78.875 N
Now,
The torque (T) exerted by water force about the fireman's will be
T = (F x d)
or
T = 78.875 N x 1.30 m
T = 102.5375 Nm
hence,
<u>A torque of 102.5375 Nm must be exerted by the fireman</u>
Answer:
8 Newton
Explanation:
Weight = force
then, given,
weight= 0.495 kg
force= 7.28 N
Now,
the total force acting on the bird = (Weight + force)N
=(0.495 + 7.28)N
=8N
hence, the total force acting on the bird is 8 N.
