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ad-work [718]
3 years ago
6

A rectangular prism has a width of 6 inches and a height of 10 inches. The volume of the rectangular prism is 300 in3. What is t

he length of the rectangular prism?
Mathematics
1 answer:
slava [35]3 years ago
7 0

it is 300 and 300

and 300

You might be interested in
1) Let f(x)=6x+6/x. Find the open intervals on which f is increasing (decreasing). Then determine the x-coordinates of all relat
brilliants [131]

Answer:

1) increasing on (-∞,-1] ∪ [1,∞), decreasing on [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum

2) increasing on [1,∞), decreasing on (-∞,0) ∪ (0,1]

x = 1 is absolute minimum

3) increasing on (-∞,0] ∪ [8,∞), decreasing on [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum

4) increasing on [2,∞), decreasing on (-∞,2]

x = 2 is absolute minimum

5) increasing on the interval (0,4/9], decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum

Step-by-step explanation:

To find minima and maxima the of the function, we must take the derivative and equalize it to zero to find the roots.

1) f(x) = 6x + 6/x

f\prime(x) = 6 - 6/x^2 = 0 and x \neq 0

So, the roots are x = -1 and x = 1

The function is increasing on the interval (-∞,-1] ∪ [1,∞)

The function is decreasing on the interval [-1,0) ∪ (0,1]

x = -1 is local maximum, x = 1 is local minimum.

2) f(x)=6-4/x+2/x^2

f\prime(x)=4/x^2-4/x^3=0 and x \neq 0

So the root is x = 1

The function is increasing on the interval [1,∞)

The function is decreasing on the interval (-∞,0) ∪ (0,1]

x = 1 is absolute minimum.

3) f(x) = 8x^2/(x-4)

f\prime(x) = (8x^2-64x)/(x-4)^2=0 and x \neq 4

So the roots are x = 0 and x = 8

The function is increasing on the interval (-∞,0] ∪ [8,∞)

The function is decreasing on the interval [0,4) ∪ (4,8]

x = 0 is local maximum, x = 8 is local minimum.

4) f(x)=6(x-2)^{2/3} +4=0

f\prime(x) = 4/(x-2)^{1/3} has no solution and x = 2 is crtitical point.

The function is increasing on the interval [2,∞)

The function is decreasing on the interval (-∞,2]

x = 2 is absolute minimum.

5) f(x)=8\sqrt x - 6x for x>0

f\prime(x) = (4/\sqrt x)-6 = 0

So the root is x = 4/9

The function is increasing on the interval (0,4/9]

The function is decreasing on the interval [4/9,∞)

x = 0 is local minimum, x = 4/9 is absolute maximum.

5 0
3 years ago
Answer please I’m dying from math
charle [14.2K]

Answer:

\huge\boxed{\text{D)} \  15x^4 + 2x^3 - 8x^2 - 22x - 15}

Step-by-step explanation:

We can solve this multiplication of polynomials by understanding how to multiply these large terms.

To multiply two polynomials together, we must multiply each term by each term in the other polynomial. Each term should be multiplied by another one until it's multiplied by all of the terms in the other expression.

  • <em>We can do this by focusing on one term in the first polynomial and multiplying it by </em><em>all the terms</em><em> in the second polynomial. We'd then repeat this for the remaining terms in the second polynomial.</em>

Let's first start by multiplying the first term of the first polynomial, 3x^2, by all of the terms in the second polynomial. (5x^2+4x+5)

  • 3x^2 \cdot  5x^2 = 15x^4
  • 3x^2 \cdot 4x = 12x^3
  • 3x^2 \cdot 5 = 15x^2

Now, we can add up all these expressions to get the first part of our polynomial. Ordering by exponent, our expression is now

  • \displaystyle 15x^4 + 12x^3 + 15x^2

Now let's do the same with the second term (-2x) and the third term (-3).

  • -2x \cdot 5x^2 = -10x^3  
  • -2x \cdot 4x = -8x^2
  • -2x \cdot 5 = -10x
  • Adding on to our original expression: \displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 10x

  • -3 \cdot 5x^2 = -15x^2
  • -3 \cdot 4x = -12x
  • -3 \cdot 5 = -15
  • Adding on to our original expression: \displaystyle 15x^4 + 12x^3 - 10x^3 + 15x^2 - 8x^2 - 15x^2 - 10x - 12x - 15

Phew, that's one big polynomial! We can simplify it by combining like terms. We can combine terms that share the same exponent and combine them via their coefficients.

  • 12x^3 - 10x^3 = 2x^3
  • 15x^2 - 8x^2 - 15x^2 = -8x^2
  • -10x - 12x = -22x

This simplifies our expression down to 15x^4 + 2x^3 - 8x^2 - 22x - 15.

Hope this helped!

7 0
2 years ago
Read 2 more answers
Hola me podrían ayudar por favor. Convertir las fracciones a decimales y ubicar a los decimales en la recta numérica. a. 2/3 b.
NISA [10]

Answer:

Step-by-step explanation:

a decimal

2/3 = 0.7

8/5 = 1.6

-5/2 = -2.5

7/4 = 1.8

9/2 =  4.5

-11/3 = -3.7

13/5 = 2.6

-7/4 = -1.8

Esto es solo un bosquejo del número, usando un gráfico, use 0.1 para una unidad en la recta numérica.

-  ________________________________________________________ +

  |    |     |      |     |       |      |       |     |     |     |    |       |     |     |      |     |     |       |            

-5  -4 -3.7  -3 -2.5  -2  -1.8   -1    0  0.7  1   1.6  1.8  2   2.6   3   4   4.5   5

8 0
3 years ago
Find the approximate difference in the area of the two circles shown below. Use 3.14 for pi.
Kobotan [32]

Answer:

b answer

Step-by-step explanation:

8 0
3 years ago
What is 3.25 x $1.40
Korolek [52]

Answer:

if you make the 3.5 equal 7/2

and the 1.40 equal 7/5 its will be more easier

so7/5 × 7/2 its 4.9

sorry guys its not 4.9 i made mistake with 3.25 i was thinking that it was 3.50 any wwy

i have good method too

we can make 3.25 equal 13/4 and 1.40 equal 7/5 the multiply it

we will find 91/20 but we have problem its The 10 dont worry we can take the 10 from the both number and we will get 9.1/2 and We can devide easily now and the answer is 4.55

sorry iam trying so hard to speak engilish well sorry if u cannot understand me big respet for all the students

8 0
3 years ago
Read 2 more answers
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