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Semenov [28]
3 years ago
7

A huge cannon is assembled on an airless planet having insignificant axial spin. The planet has a radius of 5.00 × 106 m and a m

ass of 1.46 × 1023 kg. The cannon fires a projectile straight up at 2000 m/s. An observation satellite orbits the planet at a height of 1000 km. What is the projectile's speed as it passes the satellite? (G= 6.67 × 10-11 N · m2/kg2)
Physics
1 answer:
Nata [24]3 years ago
8 0

Answer:

1830 m /s

Explanation:

The potential energy of the projectile at  the surface of planet

- G x 1.46 x 10²³ m  / 5 x 10⁶

Kinetic energy at surface

1/2 m v²

Total energy = - G x 1.46 x 10²³ m  / 5 x 10⁶ + 1/2  m v²

- 6.67 X 10⁻¹¹ x 1.46 x 10²³ /5 x 10⁶  m + 1/2 m x 2000²

- 1.947 x 10⁶ m + 2m x 10⁶

=  .053  x 10⁶ m

Potential energy of projectile at 1000 km height

= - G x 1.46 x 10²³ m  / 6 x 10⁶

= -  1.6225 x 10⁶  m J  

Total energy

= - 1.6225 x 10⁶ + 1/2 m V ²

Applying conservation of energy in gravitational field at surface and height

- 1.6225 x 10⁶  m + 1/2 m V ² = .053  x 10⁶ m

1/2 V ²  = ( .053 + 1.6225 ) x 10⁶

1/2 V² = 1.6755  x 10⁶ m /s

V = 1.83 X 10³ m/s

1830 m /s

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You are hiking along a trail in a wide, dry canyon where the outdoor temperature is T = 29.5° C. To determine how far you are aw
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Answer:

<em>The canyon is approximately 314 meters away</em>

Explanation:

<u>Speed of Sound</u>

If we emit sounds in an open space where a large obstacle (like a mountain) is expected to return the sounds, then it will travel forth and back at a given speed for a certain time. We can assume the speed of sound is constant, so we could know the approximate distance of the mountain (or canyon in our case) by the known formula.

x=v_st

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We have T=29.5^oC, so

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