Yes. Displacement is a vector, as opposed to distance, which is a scalar. Since displacement is a vector quantity, the negative sign represents direction. As with velocity and acceleration, it just comes down to how you define your coordinate system
Answer:
a) 6.26 m/s
b) 7.67 m/s
Explanation:
The potential energy at height h0 is initially ...
PE0 = mgh0
At height h1, the potential energy is ...
PE1 = mgh1
The difference in potential energy is converted to kinetic energy:
PE0 -PE1 = KE1 = (1/2)m(v1)^2
Solving for v1, we have ...
mg(h0 -h1) = (1/2)m(v1)^2
2g(h0 -h1) = (v1)^2
v1 = √(2g(h0 -h1))
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a) When the body is 1 m high, its speed is ...
v = √(2(9.8)(3 -1)) ≈ 6.26 m/s . . . at 1 m high
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b) When the body is 0 m high, its speed is ...
v = √(2(9.8)(3 -0)) ≈ 7.67 m/s . . . when it reaches the ground
Answer:
a) F_{e} - F_{m} = 0, b) v = 666.67 m / s
Explanation:
For the proton to move y-axis the sum of the electric and magnetic force must be zero, therefore
= 0
a) ∑ F = 0
F_{e} - F_{m} = 0
b) we write the forces
q E = q v B
v = E / B
Let's calculate
v = 300 / 0.45
v = 666.67 m / s
Answer:
the mass of a mercury with volume of 263mL = 3559.3 g or 3.56 kg
Explanation:
given:
263 mL liquid mercury
find:
What is the mass of mercury
we know that the density of mercury = 13.5336 g/mL.
now, calculate the mass = volume x density
plugin values into the formula
mass = 263 mL x 13.5336 g/mL.
mass = 3559.3 g or 3.56 kg
therefore,
the mass of a mercury with volume of 263mL = 3559.3 g or 3.56 kg
Answer:
Explanation:
For a string of length L clamped down on both ends , for fundamental mode of vibration
2 . λ / 4 = L
= λ / 2 = L
λ = 2 L
For other modes , the formula is
n . λ/2 = L where n is an integer .
λ = 2L / n
if n = 6
λ = 2L / 6
= L/3
So wavelength = L/3 is possible .
