Answer:
Explanation:
initial velocity, u = 43 m/s
final velocity, v = 3.38 m/s
time, t = 70 sec
acceleration, a = v - u / t
3.38 - 43 / 70
= -39.62/ 70
= <em><u>-0.56 m/s^2</u></em>
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Free fall distance h
122.583
m
Free fall velocity v
49.0333
m/s
=
176.52
km/h
Answer:
(a) θ = 55.85 degree
(b) 7.89 km
Explanation:
Using vector notations
A = 1.88 km south = 1.88 (- j) km = - 1.88 j km
B = 9.05 km 47 degree north of east
B = 9.05 ( Cos 47 i + Sin 47 j) km
B = (6.17 i + 6.62 j) km
Net displacement is
D = A + B
D = - 1.88 i + 6.17 i + 6.62 j = 4.29 i + 6.62 j
(a) Angle made with positive X axis
tanθ = 6.62 / 4.29 = 1.474
θ = 55.85 degree
(b) distance =
distance = 7.89 km
Answer:
e = 12.72 V
Explanation:
given,
radius of circular coil = 0.12 m
number of turns, N = 20
magnetic field, B = 1.6 T
frequency, f = 1.4 Hz
maximum emf = ?
∅ = N A B cos ωt
emf
e = N A B ω sin ωt
for maximum induced emf
e = N A B ω
ω = 2 π f
ω = 2 π x 1.4 = 8.79 rad/s
e = 20 x π x r² x B x ω
e = 20 x π x 0.12² x 1.6 x 8.79
e = 12.72 V
hence, the maximum value of induced emf is equal to e = 12.72 V