The easiest way is to use the Law of Gay-Lussac. This law states that there is a direct relation between the temperature in Kelvin of a gas and the pressure.
Then, namig p the pressure and T the temperature in Kelvin and using subscripts for every state:
p/T is constant ==> p_1 / T_1 = p_2/T_2
From which you obtain:
p_2 = [p_1 / T_1] * T_2
T_1 = 33.0 + 273.15 = 306.15 K
T _2 = 21.4 + 273.15 = 294.55 K
p_1 = 1014 kPa
p_2 = 1014 kPa * 294.55 K / 306.15 K = 975.6 kPa
Answer: i think its A diatomic compound..
Explanation: hope i helped! sorry if im wrong!
For this problem, we use the Beer Lambert's Law. Its usual equation is:
A = ∈LC
where
A is the absorbance
∈ is the molar absorptivity
L is the path length
C is the concentration of the sample solution
As you notice, we only have to find the absorbance. But since we are not given with the molar absorptivity, we will have to use the modified equation that relates % transmittance to absorbance:
A = 2 - log(%T)
A = 2 - log(27.3)
A = 0.5638
<h3><u>Answer</u>;</h3>
a. 3 molecules 3 carbon
b. 6 molecules 18 carbon
c. 6 molecules 18 carbon
d. 5 molecules 15 carbon
e. 3 molecules 15 carbon
f. 3 molecules 15 carbon
<h3><u>Explanation</u>;</h3>
- In the Calvin cycle, carbon atoms from CO2 are ncorporated into organic molecules and then used to build three-carbon sugars, a process that is fueled by, and dependent on, ATP and NADPH from the light reactions.
- Calvin cycle take place in the stroma. Reactions of Calvin cycle are divided into three main stages: carbon fixation, reduction, and regeneration of the starting molecule.
- During carbon fixation, a CO2 molecule combines with a five carbon acceptor molecule ribulose-1,5-bisphosphate. The result is a six carbon compound that splits to two three carbon compound, 3-PGA.
- During reduction; ATP and NADPH are used to convert the 3-PGA molecules into molecules of a three-carbon sugar, glyceraldehyde-3-phosphate.
- Finally during regeneration, some G3P molecules are used to make glucose while others are recycled to regenerate RuBP acceptor.