Ask question

Ask question

All categories

2 years ago

7

The accepted value for R is 0.08206 L·atm/K·mol or 8.314 L·kPa/K·mol, depending on the unit of pressure used. (Your answer may d

iffer slightly due to rounding.)
How close was your calculation?

1 answer:

Alecsey [184]2 years ago

8 0

Answer:

poop

Explanation:

You might be interested in

The electron configuration of an element is 1s2 2s2 2p1. How many valance electrons does the element have. 1,2,3 or 4

kotykmax [81]

Answer:

3

Explanation:

5 0

2 years ago

Read 2 more answers

Determine the rate of a reaction that follows the rate law: rate = k[A]^m[B]^n, where k = 1.5

White raven [17]

Really I appreciate you letting you guys sleep you good though I love it all I gotta see you soon buddy I’m

3 0

1 year ago

Hey can someone pls help me answer these questions? It should be easy maybe. It’s just science. The question just won’t to know

miskamm [114]

Hehehehwgwgw. Be the hardest thing ever for a long day and I have a windows

6 0

2 years ago

9.05 mol of oxygen gas to g of oxygen gas

NARA [144]

Molar mass of oxygen gas:

O₂ = 16 * 2 = 32.0 g/mol

1 mole O₂ -------------- 32.0
9.05 mole O₂ ---------- ?

Mass = 9.05 * 32.0

Mass = 289.6 g of O₂

hope this helps!

7 0

2 years ago

Antarctica, almost completely covered in ice, has an area

Marysya12 [62]

<u>Answer:</u> The mass of ice is $2.39\times 10^{22}g$

<u>Explanation:</u>

We are given:

Area of Antarctica = $5,500,000mi^2=5,500,000\times 2.59\times 10^{10}=142.45\times 10^{15}cm^2$ (Conversion factor: $1mi^2=2.59\times 10^{10}cm^2$ )

Height of Antarctica with ice = 7500 ft.

Height of Antarctica without ice = 1500 ft.

Height of ice = 7500 - 1500 = 6000 ft = $182.88\times 10^3cm$ (Conversion factor: 1 ft = 30.48 cm)

To calculate mass of ice, we use the equation:

$\text{Density of a substance}=\frac{\text{Mass of a substance}}{\text{Volume of a substance}}$

We are given:

Density of ice = $0.917g/cm^3$

Volume of ice = Area × Height of ice = $142.45\times 10^{15}cm^2\times 182.88\times 10^3cm=26051.26\times 10^{18}cm^3$

Putting values in above equation, we get:

$0.917g/cm^3=\frac{\text{Mass of ice}}{26051.26\times 10^{18}cm^3}\\\\\text{Mass of ice}=(0.917g/cm^3\times 26051.26\times 10^{18}cm^3=2.39\times 10^{22}g$

Hence, the mass of ice is $2.39\times 10^{22}g$

5 0

3 years ago