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3 years ago

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The accepted value for R is 0.08206 L·atm/K·mol or 8.314 L·kPa/K·mol, depending on the unit of pressure used. (Your answer may d

iffer slightly due to rounding.)
How close was your calculation?

1 answer:

Alecsey [184]3 years ago

8 0

Answer:

poop

Explanation:

You might be interested in

When a chemical reaction occurs, what always stays the same between reactants and products?

BlackZzzverrR [31]

The total number of atoms remains unchanged, <em>always.</em> But the chemical properties change :)

please rate brainliest! thanks!

7 0

3 years ago

instrucions classify the following reactions as synthesis, decomposition,single replacement, double replacement, or combustion.

My name is Ann [436]

Answer:

There are no specific equations but here what i can give you:

1. Synthesis -- A synthesis reaction is a chemical change in which two or more substances react to form a single new substance.

In all synthesis reactions, there is a single product that is a compound!

2. Decomposition -- A decomposition reaction is a chemical change in which a single compound breaks down into two or more simpler products. (This is the opposite of synthesis reactions!)

Most decomposition reactions require energy in the form of heat, light, and electricity.

3. Single Replacement -- A single-replacement reaction is a chemical change in which one element replaces a second element in a compound. You can identify a single-replacement reaction by noting that both the reactants and the products consist of an element and a compound.

4. Double Replacement -- A double-replacement reaction is a chemical change involving an exchange of positive ions between two compounds.

For a double replacement reactions to occur, one of the following is usually true:

- One of the products is only slightly soluble and precipitates from solutions.

- One of the products is a gas.

- One product is a molecular compound such as water.

5. Combustion -- A combustion reactions is a chemical change in which an element or a compound reacts with oxygen, often producing energy in the form of heat or light.

A combustion reactant always involves oxygen as a reactant. (If the supply of oxygen is limited, then the combustion will not be complete.)

The other reactant is a hydrocarbon, which is a compound composed of hydrogen and carbon and the complete combustion of a hydrocarbon produces CO2 and H2O.

Hydrocarbons include methane, propane, and butane.

I really hope this helps you!

3 0

3 years ago

This elememt derived its name from the latin

aniked [119]

There are many elements with a Latin name such as sodium, iron, potassium which all of their symbols refer to their Latin name, hope this helps.

7 0

3 years ago

If a 1.0x10-5 L sample of agas at 2.0x106 atm isreleased until it is equal to0.275 atm, what would thenew volume of the gas be?

Greeley [361]

Answer:

Explanation:

Here, we want to get the new volume of the gas

What we need to know is the law that connects volume and pressure at constant temperature

The law that supports this is the Boyle's law

It states that the volume of a given mass of gas is inversely proportional to its pressure at constant temperature

Mathematically, we can have this as represented as:

$\begin{gathered} P_1V_1=P_2V_2 \\ P_1\text{ = 2.0 }\times10^{6\text{ }}\text{ atm} \\ V_1\text{ = 1.0 }\times10^{-5}\text{ L} \\ P_2\text{ =0.275 atm} \\ V_2\text{ = ?} \end{gathered}$

We can proceed mathematically to solve as follows;

$undefined$

5 0

1 year ago

Part a cyclohexane has a freezing point of 6.50 ∘c and a kf of 20.0 ∘c/m. What is the freezing point of a solution made by disso

Andrei [34K]

The mathematical expression for the depression in freezing point is given as:

$\Delta T_{f}= k_{f}m$

where, $\Delta T_{f}$ = depression in freezing point

$k_{f}$ = molal depression constant (20.0 $^{o}Ckg/mole$ )

m = molality

Molality is defined as the ratio of number of moles of solute to the kg of the solvent

Number of moles = $\frac{given mass in g}{molar mass}$

given mass of biphenyl solute = 0.925 g

Molar mass of biphenyl = 154.21 g/mol

Put the values,

number of moles of biphenyl = $\frac{0.925 g}{154.21 g/mol}$

= $0.0059 mole$

Molality = $\frac{number of moles of biphenyl solute}{mass of the solvent in kg}$

Mass of cyclohexane solvent = 25.0 g

Convert g into kg: 1 kg = 1000 g

Thus, mass of cyclohexane = $\frac{25.0}{1000}$

= 0.025 kg

Now, put the values in the formula of molality:

Molality = $\frac{0.0059 mole}{0.025 kg}$

= 0.236 mole/kg or 0.236 m.

Calculate the depression in freezing point:

$\Delta T_{f}= 20.0^{o}C kg/mole\times 0.236 mole/kg$

= $4.72 ^{o}C$

Now, $\Delta T_{f} = T_{solvent} - T_{solution}$

$4.72 ^{o}C = 6.50^{o}C - T_{solution}$

$T_{solution} = 6.50^{o}C- 4.72 ^{o}C$

= $1.78^{o}C$

Hence, freezing point of the solution is $1.78^{o}C$ .

4 0

3 years ago

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