Answer:
0.357 g He
Explanation:
1 mol of gas at STP = 22.4 L
2.00 L * 1 mol/22.4 L = 0.08929 mol He
M(He) = 4.00 g/mol
0.08929 mol He * 4.00 g/ 1 mol He = 0.357 g He
We are going to use Henry's law:
when C1/P1 = C2/P2
at a constant temperature.
and when the C1 and C2 are the concentration of the gases ( the solubility)
and P1 and P2 is the Pressure 1 and pressure 2
and when 760 mmHg = 1 atm
so, by substitution:
1.6 g/L / 1 atm = C2 /2.5 atm
∴C2 = 1.6g/L *2.5atm /1 atm
= 4 g/L
Mole number of 75 g is 0.4 mol. NO2 is 0.8 mol and is 36.8 g.
This type of energy would be called reaction energy.
