Given information :
G = 173.3 KJ
H = 180.7 KJ
T = 303.0 K
S = unknown (?)
By using the given formula : G = H - TS , we can calculate the value of 'S'
On rearranging the formula we get : S = 
Plug in the value of G , H and T in the above formula :
S = 
S = 0.02442 
The question is incomplete, here is the complete question:
What volume (mL) of the partially neutralized stomach acid having concentration 2 M was neutralized by 0.1 M NaOH during the titration? (portion of 25.00 mL NaOH sample was used; this was the HCl remaining after the antacid tablet did it's job)
<u>Answer:</u> The volume of HCl neutralized is 1.25 mL
<u>Explanation:</u>
To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of stomach acid which is HCl
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the volume of HCl neutralized is 1.25 mL