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2 years ago

What is an element?

Chemistry

1 answer:

const2013 [10]2 years ago

6 0

Answer:

B) a substance made of just one kind of atom that cannot be broken down into something simpler

Explanation:

Elements are what you find on the periodic table of elements.

Take oxygen, for example. You can have one or multiple atoms, but if they are all oxygen atoms it's an element.

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A sample of HI (9.30×10^−3mol) was placed in an empty 2.00 L container at 1000 K. After equilibrium was reached, the concentrati

Sedaia [141]

Answer:

The answer is "29.081"

Explanation:

when the empty 2.00 L container of 1000 kg, a sample of HI (9.30 x 10-3 mol) has also been placed.

$\text{calculating the initial HI}= \frac{mol}{V}$

$=\frac{9.3 \times 10 ^ -3}{2}$

$=0.00465 \ Mol$

$\text{Similarly}\ \ I_2 \ \ \text{follows} \ \ H_2 = 0 }$

Its density of I 2 was 6.29x10-4 M if the balance had been obtained, then we have to get the intensity of equilibrium then:

$HI = 0.00465 - 2x\\\\ I_{2} \ eq = H_2 \ eq = 0 + x \\\\$

It is defined that:

$I_2 = 6.29 \times 10^{-4} \ M \\\\x = I_2 \\\\$

$HI \ eq= 0.00465 - 2x \\$

$=0.00465 -2 \times 6.29 \times 10^{-4} \\\\ = 0.00465 -\frac{25.16 }{10^4} \\\\ = 0.003392\ M$

Now, we calculate the position:

For the reaction $H 2(g) + I 2(g)\rightleftharpoons 2HI(g)$ , you can calculate the value of Kc at 1000 K.

data expression for Kc

$2HI \rightleftharpoons H_2 + I_2 \\\\\to Kc = \frac{H_2 \times I_2}{HI^2}$

$= \frac{6.29\times10^{-4} \times 6.29 \times 10^{-4}}{0.003392^2} \\\\= \frac{6.29\times 6.29 \times 10^{-8}}{0.003392^2} \\\\= \frac{39.564 \times 10^{-8}}{1.150 \times 10-5} \\\\= 0.034386$

calculating the reverse reaction

$H_2(g) + I_2(g)\rightleftharpoons 2HI(g)$

$Kc = \frac{1}{Kc} \\\\$

$= \frac{1}{0.034386}\\ \\= 29.081\\$

7 0

2 years ago

Which of the following instruments is a combination of a percussion and a stringed instrument?

murzikaleks [220]

Answer:B

Explanation:

3 0

2 years ago

Which is the correct name for p2o5? phosphorus dioxide phosphorus pentoxide diphosphorus pentoxide diphosphorus hexaoxide

Elenna [48]

Correct option:

The correct name for $P_{2}O_{5}$ is diphosphorus pentoxide.

Why $P_{2}O_{5}$ is called diphosphorus pentoxide?

$P_{2}O_{5}$ is commonly known as diphosphorus pentoxide.

Phosphorus pentoxide has an intriguing property in that $P_{2}O_{5}$ is actually its empirical formula, whereas $P_{4}O_{10}$ is its actual molecular formula.

However, the name of the chemical was obtained from its empirical formula rather than from its molecular formula. The official name for this substance is diphosphorus pentoxide.

Oxygen-containing binary compounds have "oxide" as their "last name." Phosphorus is the "first name."

We list each atom's numbers below:

The di- and Penta- prefixes are used to indicate the presence of two and five oxygen atoms, respectively, in the molecule.

Learn more about diphosphorus pentoxide here,

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6 0

1 year ago

How do changes to genes affect the traits of an organism?

vodka [1.7K]

Changes to genes can affect the phenotypic traits of an organism, making them look differently.

5 0