What s the most direct way to differentiate between types of epithlial tissue

. How does temperature change with altitude in the troposphere?

olga55 [171]

The troposphere is hotter near the Earth's surface because heat from the Earth warms this air. As the altitude increases the number of air molecules decreases, the average of their kinetic energy decreases.

Does this help?

if it does please mark me brainliest! thanks:)

7 0

2 years ago

The primary determinant of basal metabolic rate (bmr) is __________. the primary determinant of basal metabolic rate (bmr) is __

babunello [35]

I believe the primary determinant of basal metabolic rate is the Lean Body Mass. Basal metabolic is the rate of energy expenditure per unit time by animals at rest. It comprises the processes that the body requires to function. It is the amount of energy per unit time that a person need to keep the body operational at a state of rest.

4 0

3 years ago

What would happen to the mountain lion population if the deer became extinct?

Fofino [41]

The mountain lion population will decrease.

7 0

3 years ago

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the solution inside a plant cell is approximately a 1% saline solution. in a 25% nacl solution the cytoplasm of a plant cell wil

mrs_skeptik [129]

The cell has 1% concentration of the salt. The external environment is highly concentrated with 25% saline solution. This will lead to release of water outside the cell, by passive diffusion from a region of high conentration of solvent to lower concentration. Thus, the cell will shrink.

3 0

3 years ago

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When pink sweet peas were self-pollinated and the seeds were collected and sown, the following flower colors were obtained: Red

Pavlova-9 [17]

Answer:

c. 1:2:1

The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

Explanation:

If flower color were determined by a gene showing incomplete dominance, the possible genotypes and phenotypes are as follows:

RR- red
ww - white
Rw - pink

If pink sweet peas are self-pollinated, then a cross between two heterozygous individuals is done (Rw x Rw).

From this cross the expected ratios are:

1/4 RR (red)
2/4 Rw (pink)
1/4 ww (white)

So the null hypothesis is that the observed results exhibit a 1:2:1 ratio.

<h3>Chi square test</h3>

$X^{2} = \sum \frac{(Observed - Expected)^2}{Expected}$

The observed frequencies were:

34 Red
76 Pink
40 White

Total 150

The expected frequencies for our null hypothesis are:

1/4 x 150 = 37.5 Red
2/4 x 150 = 75 Pink
1/4 x 150 = 37.5 white

$X^{2} = \frac{(34- 37.5)^2}{37.5} + \frac{(76- 75)^2}{75} + \frac{(40- 37.5)^2}{37.5}$

$X^2=0.5067$

The degrees of freedom (DF) are calculated as number of phenotypes - 1; in this case DF = 3-1 = 2.

If we look at the Chi square table, for 2 DF and a probability of p0.05, the critical value is 5.991

Our X^2 value of 0.5067 is less than the critical value, so we do not reject the null hypothesis. The results are consistent with incomplete dominance for this trait, with pink flowers being heterozygous.

8 0

3 years ago