1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
STALIN [3.7K]
3 years ago
7

Solve the system of equations using any method. If there is no solution, write "Inconsistent". If there are infinitely many solu

tions, write "Dependent." ( 2x +3y 9 3x + 2y 11 93 (10

Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

consistent

Step-by-step explanation:

all work is shown and pictured

You might be interested in
Evaluate: 955-105 x 4 +118
drek231 [11]

Answer: −420x+1073

Step-by-step explanation:

Let's simplify step-by-step.

955−105x(4)+118=955+−420x+118

Combine Like Terms:

=955+−420x+118=(−420x)+(955+118)=−420x+1073

Answer: =−420x+1073

6 0
3 years ago
Read 2 more answers
6/(x+1)-5/2=6/(3x+3)
jolli1 [7]
If you would like to calculate 6/(x+1)-5/2=6/(3x+3), you can do this using the following steps:

6/(x+1)-5/2=6/(3x+3)
6/(x+1)-5/2=6/(3(x+1))      /*(x+1)
6 - 5/2 * (x+1) = 6/3
6 - 2 = 5/2 * (x+1)
4 = 5/2 * (x+1)     /*2/5
4 * 2/5 = x + 1
8/5 - 1 = x
x = 8/5 - 5/5 = 3/5

The correct result would be 3/5.
6 0
3 years ago
I need answer on this graphing va substitution.Problem 7 I tried to solve it but not sure that’s correct
Bond [772]

Given the system of equations:

\begin{gathered} 2x+9y=27 \\ x-3y=-24 \end{gathered}

To solve it by substitution, follow the steps below.

Step 1: Solve one linear equation for x in terms of y.

Let's choose the second equation. To solve it for x, add 3y to each side of the equations.

\begin{gathered} x-3y=-24 \\ x-3y+3y=-24+3y \\ x=-24+3y \end{gathered}

Step 2: Substitute the expression found for x in the first equation.

\begin{gathered} 2x+9y=27 \\ 2\cdot(-24+3y)+9y=27 \\ -48+6y+9y=27 \\ -48+15y=27 \end{gathered}

Step 3: Isolate y in the equation found in step 2.

To do it, first, add 48 to both sides.

\begin{gathered} -48+15y=27 \\ -48+15y+48=27+48 \\ 15y=75 \end{gathered}

Then, divide both sides by 15.

\begin{gathered} \frac{15y}{15}=\frac{75}{15} \\ y=5 \end{gathered}

Step 4: Substitute y by 5 in the relation found in step 1 to find x.

\begin{gathered} x=-24+3y \\ x=-24+3\cdot5 \\ x=-24+15 \\ x=-9 \end{gathered}

Answer:

x = -9

y = 5

or (-9, 5)

Also, you can graph the lines by choosing two points from each equation, according to the picture below.

7 0
1 year ago
Help figuring out what to do on here
Andreyy89
You got to use the formula provided to solve the problem! Have confidence! you can do it!
7 0
3 years ago
A courier service company wishes to estimate the proportion of people in various states that will use its services. Suppose the
Orlov [11]

Answer:

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.05, n = 212, \mu = 0.05, s = \sqrt{\frac{0.05*0.95}{212}} = 0.015

What is the probability that the sample proportion will differ from the population proportion by less than 0.03?

This is the pvalue of Z when X = 0.03 + 0.05 = 0.08 subtracted by the pvalue of Z when X = 0.05 - 0.03 = 0.02. So

X = 0.08

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{0.08 - 0.05}{0.015}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 0.02

Z = \frac{X - \mu}{s}

Z = \frac{0.02 - 0.05}{0.015}

Z = -2

Z = -2 has a pvalue of 0.0228

0.9772 - 0.0228 = 0.9544

95.44% probability that the sample proportion will differ from the population proportion by less than 0.03.

6 0
3 years ago
Other questions:
  • Solve for x 27^(2x+4)=1/9^(x-46)
    12·1 answer
  • Choose the fraction that goes in the blank? 1/2 < _ < 4/5
    8·2 answers
  • Why can it help to line up the decimal points before comparing and ordering numbers with decimals?
    8·1 answer
  • Rewrite y =<img src="https://tex.z-dn.net/?f=%5Csqrt9%7Bx%7D%20%2B45" id="TexFormula1" title="\sqrt9{x} +45" alt="\sqrt9{x} +45"
    15·1 answer
  • The mean of 87 104 99
    10·2 answers
  • Reese is selling lemonade at the parade. He gets to keep 30% of the money he collects. A large lemonade is $4.00 and a small lem
    13·1 answer
  • What is the area of the triangle in the diagram?
    7·1 answer
  • Solve all 5 questions for 62 points if they are correct you will be marked brainiest
    5·2 answers
  • Please help! Need to turn it in by tomorrow!
    6·2 answers
  • FOR 50 POINTS. HELP ASAP!!!! John is looking at the eagle on top of a building. The height of the building is 120 ft.
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!