How many electrons are transferred during the formation of one molecule of al2o3?

1 answer:

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Answer:
Six electrons are transferred in the formation of Al₂O₃.

Explanation:
Aluminium metal and Oxygen react to form Al₂O₃ as,

2 Al + 3/2 O₂ → Al₂O₃

Oxidation number of Al on left hand side is zero, while than on right hand side in Al₂O₃ is +3. Means it has lost 3 electrons per one atom and six electrons per two atoms. Also, the oxidation number of O at left hand side in O₂ is zero, while that in Al₂O₃ it is -2 per atom and -6 per 3 atoms.

So, two Al atoms have lost 6 electrons and 3 O atoms have gained six electrons.

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Ba(oh)2+H3po4+h2o how is it balance ?

Igoryamba

Answer:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Explanation:

Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 3 atoms of Ba on the right side and 1atom on the left side. It can be balance by putting 3 in front of Ba(OH)2 as shown below:

3Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O

There are 2 atoms of P on the right side and 1atom on the left. It can be balance by putting 2 in front of H3PO4 as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + H2O

Now, there are a total of 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:

3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O

Now the equation is balanced as the numbers of the atoms of the different elements present on both sides are equal

4 0

3 years ago

Calculate the number of atoms in 112 g of iron.

mr_godi [17]

Answer:

1 mole of iron (Fe) = 56 g (molar mass)

Since 56 g of iron = 1 mol.

Therefore, 112 g of iron= 1/ 56 ×112 mol = 2 mol.

Explanation:

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