The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g
<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
- Volume = 250 mL = 250 / 1000 = 0.25 L
- Molarity = 0.3 M
Mole = Molarity x Volume
Mole of Na₂SO₄ = 0.3 × 0.25
Mole of Na₂SO₄ = 0.075 mole
<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
- Molar mass of Na₂SO₄ = 142.05 g/mol
- Mole of Na₂SO₄ = 0.075 mole
Mass = mole × molar mass
Mass of Na₂SO₄ = 0.075 × 142.05
Mass of Na₂SO₄ = 10.65 g
Thus, 10.65 g of Na₂SO₄ is needed to prepare the solution.
Learn more about molarity:
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If it’s a multiple choice question A is the correct answer
4mx2mx3m
Answer:
Explanation:
Chemical equation:
FeCl₃ + NaOH → Fe(OH)₃ + NaCl
Balanced chemical equation:
FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl
Step 1:
FeCl₃ + NaOH → Fe(OH)₃ + NaCl
Fe = 1 Fe = 1
Cl = 3 Cl = 1
Na = 1 Na = 1
OH = 1 OH = 3
Step 2:
FeCl₃ + 3NaOH → Fe(OH)₃ + NaCl
Fe = 1 Fe = 1
Cl = 3 Cl = 1
Na = 3 Na = 1
OH = 3 OH = 3
Step 3:
FeCl₃ + 3NaOH → Fe(OH)₃ + 3NaCl
Fe = 1 Fe = 1
Cl = 3 Cl = 3
Na = 3 Na = 3
OH = 3 OH = 3
Now we the equation is completely balanced and follow the law of conservation of mass because there are equal number of atoms of each elements are present on both side.
According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.
This law was given by french chemist Antoine Lavoisier in 1789. According to this law mass of reactant and mass of product must be equal, because masses are not created or destroyed in a chemical reaction
.
Type of reaction:
It is double displacement reaction.
Double replacement:
It is the reaction in which two compound exchange their ions and form new compounds.
AB + CD → AC +BD
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