Social media offer a way for brands to invite consumers to engage and interact while they develop shareable content.
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What is a Brand?</h3>
A brand is an intangible marketing concept that helps people identify a company, product, or individual. People often confuse brands with things like slogans, or other recognizable marks, which are marketing tools that help promote goods and services.
Thus, Social Media plays a vital role in encouraging a brand, and through social media, brands can seed many forms of content in social communities as they try to boost engagement and sharing.
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Corporate strategy correlates with achieving the highest profit margins, and ROI attracts more customers.
Strategy is the long-term plan that a business creates to achieve its desired future state. Your strategy includes your company goals, the type of product/service you want to develop, the customers you want to sell to, and the markets you want to serve profitably.
His three examples of these corporate strategies are applicable at certain times in the life of a company. Grow: Expand your business and increase your profits. Stability: To maintain continuous business operations. Renewal: To revive a declining business.
According to Porter's general strategy model, an organization has his three basic strategic options for achieving competitive advantage. These are cost leadership, differentiation and focus.
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Answer:
I procastinate to do my work that was due 4 days ago
Answer:
A) R(x) = 120x - 0.5x^2
B) P(x) = - 0.75x^2 + 120x - 2500
C) 80
D) 2300
E) 80
Explanation:
Given the following :
Price of suit 'x' :
p = 120 - 0.5x
Cost of producing 'x' suits :
C(x)=2500 + 0.25 x^2
A) calculate total revenue 'R(x)'
Total Revenue = price × total quantity sold, If total quantity sold = 'x'
R(x) = (120 - 0.5x) * x
R(x) = 120x - 0.5x^2
B) Total profit, 'p(x)'
Profit = Total revenue - Cost of production
P(x) = R(x) - C(x)
P(x) = (120x - 0.5x^2) - (2500 + 0.25x^2)
P(x) = 120x - 0.5x^2 - 2500 - 0.25x^2
P(x) = - 0.5x^2 - 0.25x^2 + 120x - 2500
P(x) = - 0.75x^2 + 120x - 2500
C) To maximize profit
Find the marginal profit 'p' (x)'
First derivative of p(x)
d/dx (p(x)) = - 2(0.75)x + 120
P'(x) = - 1.5x + 120
-1.5x + 120 = 0
-1.5x = - 120
x = 120 / 1.5
x = 80
D) maximum profit
P(x) = - 0.75x^2 + 120x - 2500
P(80) = - 0.75(80)^2 + 120(80) - 2500
= -0.75(6400) + 9600 - 2500
= -4800 + 9600 - 2500
= 2300
E) price per suit in other to maximize profit
P = 120 - 0.5x
P = 120 - 0.5(80)
P = 120 - 40
P = $80
