Complete Question
Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?
Answer:
Go-cart A is faster
Explanation:
From the question we are told that
The length of the track is 
The speed of A is 
The uniform acceleration of B is 
Generally the time taken by go-cart A is mathematically represented as
=> 
=> 
Generally from kinematic equation we can evaluate the time taken by go-cart B as
given that go-cart B starts from rest u = 0 m/s
So
=> 
=> 
Comparing 
we see that 
is smaller so go-cart A is faster
Normal force is mass x gravity, so mass x 9.81
That's the definition of the property called "density".
Answer:
It will take the plant 
days or 4.44 days to grow to a height of 200 inches tall.
Explanation:
From the question, the rate at which the species of the bamboo tree grows is 36 inches per day.
To determine how long it would take a plant 40 inches tall initially to grow at this rate (that is, 36 inches per day) to a height of 200 inches.
This means we will calculate the number of days it will take the plant to grow additional 160 inches ( 200 inches - 40 inches) at this rate.
Now,
If the plant grows 36 inches in 1 day
then it will grow 160 inches in x days
x = (160 inches × 1 day) / 36 inches
x = 160 / 36
x = days or 4.44 days
Hence, it will take the plant days or 4.44 days to grow to a height of 200 inches tall.
Answer:
The value is 
Explanation:
From the question we are told that
The amount of power delivered is 
The time taken is 
The wavelength is 
Generally the energy delivered is mathematically represented as
Where 
is the Planck's constant with value 
c is the speed of light with value 
So
=>
