Answer:
the frequency of the second harmonic of the pipe is 425 Hz
Explanation:
Given;
length of the open pipe, L = 0.8 m
velocity of sound, v = 340 m/s
The wavelength of the second harmonic is calculated as follows;
L = A ---> N + N--->N + N--->A
where;
L is the length of the pipe in the second harmonic
A represents antinode of the wave
N represents the node of the wave
The frequency is calculated as follows;
Therefore, the frequency of the second harmonic of the pipe is 425 Hz.
Electrons move from the atoms in the cloth to the atoms in the balloon, causing the balloon to have a negative charge
Hope this helps!!!
Answer with Explanation:
We are given that
A=3i-3j m
B=i-4 j m
C=-2i+5j m
a.
Compare with the vector r=xi+yj
We get x=2 and y=-2
Magnitude= units
By using the formula
Direction:
By using the formula
Direction of D:
b.E=-A-B+C
units
Direction of E=